Q24. - Algebra 2

Question

Find $p\left(4\right)\text{ and }p\left(-2\right)$ for the function $p\left(x\right)=2x^3-x^2+5x-7$.

Step-by-Step Solution

Answer

The value of $p\left(4\right)=125\text{ and }p\left(-2\right)=-37$.

Step 1. Write down the given information.

The given function is $p\left(x\right)=2x^3-x^2+5x-7$.

Step 2. Calculation.

Evaluating $p\left(4\right)\text{ and }p\left(-2\right)$ by plugging $x=4\text{ and }x=-2$ in given function $p\left(x\right)=2x^3-x^2+5x-7$.

$\begin{array}{c}p\left(x\right)=2x^3-x^2+5x-7 ....\left(\text{Given}\right)\\ p\left(4\right)=2{\left(4\right)}^3-{\left(4\right)}^2+5\left(4\right)-7\\ =125\\ \text{Now, }p\left(-2\right)=2{\left(-2\right)}^3-{\left(-2\right)}^2+5\left(-2\right)-7\\ =-37\end{array}$

Step 3. Conclusion.

The value of $p\left(4\right)=125\text{ and }p\left(-2\right)=-37$.