Q20.
Question
Example 1 Determine whether each relation is a function. Explain.
Step-by-Step Solution
Verified Answer
This relation is a function.
1Step 1. Given.
The given relation is:
2Step 2. To determine.
We have to find if the given relation is a function.
3Step 3. Calculation.
For a relation to be a function, we must have only one y value for each x value.
For this relation:
For x = 4, we have y = 5
For x = - 6, we have y = 5
For x = 3, we have y = 3
For x = -2, we have y = 4
So, for each x value, there is only one y-value. This implies that this relation is a function.
Other exercises in this chapter
Q18.
Examples 4 and 5 If f(x)=6x+7 and g(x)=x2−4, find each value. (P. 49)f(2)+g(−2)
View solution Q19.
Examples 4 and 5 If f(x)=6x+7 and g(x)=x2−4, find each value. (P. 49)g(−b)
View solution Q21.
Determine whether each relation is a function. Explain.
View solution Q22.
Example 1 Determine whether each relation is a function. ExplainDomainRange46–536–3–55
View solution