Q18. - Algebra 1

Question

Examples 4 and 5 If $f\left(x\right)=6x+7$ and $g\left(x\right)=x^2-4,$ find each value. (P. 49)

$f\left(2\right)+g(-2)$

Step-by-Step Solution

Answer

The value of the expression is 19.

Step 1. Apply substitution method to find value of function f x at x = 2 .

$\begin{array}{l}f\left(2\right)=6\left(2\right)+7\\ f\left(2\right)=12+7\\ f\left(2\right)=19\end{array}$

Step 2. Apply substitution method to find value of function g x at x = − 2 .

$\begin{array}{l}g\left(-2\right)={\left(-2\right)}^2-4\\ g\left(-2\right)=4-4\\ g\left(-2\right)=0\end{array}$

Step 3. Calculate the result.

$\begin{array}{l}f\left(2\right)+g\left(-2\right)=19+0\\ f\left(2\right)+g\left(-2\right)=19\end{array}$

Therefore, the value of $f\left(2\right)+g\left(-2\right)$ is 19.