Q2.

Question

Question: Label each bond in the following compounds as ionic or covalent.


a. F2b. LiBrc. CH3CH3d. NaNH2e. NaOCH2

Step-by-Step Solution

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Answer

Answer

 

 a. F2:Covalent

b. LiBr: Ionic

c. CH3CH3: Covalent

d. NaNH2:Both covalent and ionic

e. NaONH2:Both covalent and ionic

1Step-by-Step Solution Step 1: Covalent bonds

The atoms in a covalent bond have electrostatic attraction, and the reacting atoms are neutral. These bonds have low polarity and are weak. The covalent bond formation is shown below:



                               Representation of a covalent bond formation

2Step 2: Ionic bonds


The atoms in an ionic bond possess electron pairs, and the reacting atoms carry a specific electric charge, that is, either positive or negative. These bonds have high polarity and are strong. The ionic bond formation is shown below:




                                   Representation of an ionic bond formation 

3Step 3: Determination of the type of bond present

The bonds are classified as ionic or covalent based on atomic charges. Two neutral atoms will form a covalent bond, whereas two charged species will form an ionic bond.

 

 

4Step 4: Classification of compounds

The fluorine-fluorine bond in is covalent. The lithium-bromine bond in is ionic because of the presence of lithium ion and bromide ion . All the carbon-hydrogen bonds in are covalent. 

 

The two nitrogen-hydrogen bonds in are covalent, but the bond between sodium and nitrogen is ionic due to positive and negative charges on sodium and nitrogen, respectively. 

 

The three carbon-hydrogen bonds and one carbon-oxygen in are covalent, whereas the sodium-oxygen bond is ionic due to charges on the atoms.