Q18.

Consecutive sides of the figures are perpendicular. Find the area of each figure.

Verified

Answer

Area of the figure $(A) = 56$

1Step 1. Given information.

Consecutive sides of the figure is perpendicular.

2Step 2. Concept Used.

If b is the base of the reactangle and h is the height of the rectangle.

Then, the area of the rectangle is $A = b \times h$

3Step 3. Let’s calculate the area of the figure.

Measurement of first part of the figure is –height $(h) = 2,$ $b a s e (b) = 2.8$

Put the value of base and height into the formula and find the area of the figure: $\begin{matrix} A_{1} = 2.8 \times 2 \\ = 5.6 \end{matrix}$

Measurement of the second part of the figure is-height $(h) = 4,$ $b a s e (b) = 2.8$

Put the value of base and height into the formula and find the area of the figure: $\begin{matrix} A_{2} = 2.8 \times 4 \\ = 11.2 \end{matrix}$

Measurement of the third part of the figure is –height $(h) = 6,$ $b a s e (b) = 2.8$

Put the value of base and height into the formula and find the area of the figure: $\begin{matrix} A_{3} = 2.8 \times 6 \\ = 16.8 \end{matrix}$

Measurement of the fourth part of the figure is –height $(h) = 8,$ $b a s e (b) = 2.8$

Put the value of base and height into the formula and find the area of the figure: $\begin{matrix} A_{4} = 2.8 \times 8 \\ = 22.4 \end{matrix}$

Now,the total area of the figure –

$\begin{matrix} A = A_{1} + A_{2} + A_{3} + A_{4} \\ = 5.6 + 11.2 + 16.8 + 22.4 \\ = 56 \end{matrix}$

Therefore, the area of the figure $(A) = 56$