Q115P - Chemistry: Molecular Nature Of Matter And Change

Question

Each circle contains a representation of a binary compound. Determine its name, formula and molecular formula mass.

Step-by-Step Solution

Answer

 

1. Molecular Name - Nitrous Oxide

Empirical formula - ${\mathbf{N}}_{\mathbf{2}}\mathbf{O}$

Molecular Mass - 44.02 amu

1. Molecular Name –Dichlorinemonooxide

           Empirical formula - ${\mathbf{Cl}}_{\mathbf{2}}\mathbf{O}$

           Molecular Mass - 86.9 amu

Step 1: Defining binary compounds

A binary compound is a compound consisting of precisely two elements. 

Step 2:Name, molecular mass and formula for the first binary compound

Two Nitrogen atoms and one oxygen atom are present in the compound.

The molecular formula is ${\mathbf{N}}_{\mathbf{2}}\mathbf{O}$.

The name of the compound is nitrous oxide or dinitrogen monoxide.

The atomic mass of the element,

N = 14u, O = 16u

Molecular mass $\mathbf{2}\mathbf{\times }\mathbf{atomic}\mathbf{ }\mathbf{mass}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{N}\mathbf{+}\mathbf{atomic}\mathbf{ }\mathbf{mass}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{O}$

$\mathbf{=}\mathbf{2}\mathbf{\times }\mathbf{14}\mathbf{.}\mathbf{01}\mathbf{+}\mathbf{1}\mathbf{\times }\mathbf{16}\mathbf{.}\mathbf{00}\mathbf{=}\mathbf{44}\mathbf{.}\mathbf{02}\mathbf{ }\mathbf{amu}$

Step 3:Name, molecular mass and formula for the second binary compound

Two Chlorine atoms and one oxygen atom are present in the compound.

The molecular formula is, ${\mathbf{Cl}}_{\mathbf{2}}\mathbf{O}$

The name of the compound is dichlorine-monoxide .

The atomic mass of the element,$\mathbf{Cl}\mathbf{=}\mathbf{35}\mathbf{.}\mathbf{5}\mathbf{u}\mathbf{,}\mathbf{ }\mathbf{O}\mathbf{=}\mathbf{ }\mathbf{16}\mathbf{u}$

Molecular mass$\mathbf{2}\mathbf{\times }\mathbf{atomic}\mathbf{ }\mathbf{mass}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{CI}\mathbf{+}\mathbf{atomic}\mathbf{ }\mathbf{mass}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{O}$

$\mathbf{=}\mathbf{2}\mathbf{\times }\mathbf{35}\mathbf{.}\mathbf{45}\mathbf{+}\mathbf{1}\mathbf{\times }\mathbf{16}\mathbf{=}\mathbf{86}\mathbf{.}\mathbf{9}\mathbf{ }\mathbf{amu}$