Q.10.49 - An Introduction to General, Organic, and Biological Chemistry

Question

Write a balanced equation for the neutralization of each of the following:

a.${\mathrm{H}}_2{\mathrm{SO}}_4\left(aq\right) \text{and }\mathrm{NaOH}\left(aq\right)$

b. $\mathrm{HCl}\left(aq\right) \text{and }\mathrm{Fe}\left(\mathrm{OH}{)}_3\right(s)$

c.${\mathrm{H}}_2{\mathrm{CO}}_3\left(aq\right) and \mathrm{Mg}\left(\mathrm{OH}{)}_2\right(s)$

Step-by-Step Solution

Answer

a. ${\mathrm{H}}_2{\mathrm{SO}}_4\left(aq\right)+2\mathrm{NaOH}\left(aq\right)\to 2{\mathrm{H}}_2\mathrm{O}\left(l\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(aq\right)$

b. $3\mathrm{HCl}\left(aq\right)+\mathrm{Fe}\left(\mathrm{OH}{)}_3\right(s)\to 3{\mathrm{H}}_2\mathrm{O}(l)+{\mathrm{FeCl}}_3(aq)$

c.${\mathrm{H}}_2{\mathrm{CO}}_3\left(aq\right)+\mathrm{Mg}\left(\mathrm{OH}{)}_2\right(s)\to 2{\mathrm{H}}_2\mathrm{O}(l)+{\mathrm{MgCO}}_3(aq)$

Part (a) Step 1: Given Information

Write a balanced equation for the neutralization of-

${\mathrm{H}}_2{\mathrm{SO}}_4\left(aq\right)\text{ and }\mathrm{NaOH}\left(aq\right)$

Part (a) Step 2: Explanation

The balanced equation for the neutralization of ${\mathrm{H}}_2{\mathrm{SO}}_4\left(aq\right)\text{ and }\mathrm{NaOH}\left(aq\right)$ is,

${\mathrm{H}}_2{\mathrm{SO}}_4\left(aq\right)+2\mathrm{NaOH}\left(aq\right)\to 2{\mathrm{H}}_2\mathrm{O}\left(l\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(aq\right)$

The reaction of $H_{2}S{O}_4$ with NaOH gives water $H_{2}O$ and sodium sulfate salt $N{a}_{2}S{O}_4$.

Part (b) Step 1: Given Information

Write a balanced equation for the neutralization of-

$\mathrm{HCl}\left(aq\right)\text{ and }\mathrm{Fe}\left(\mathrm{OH}{)}_3\right(s)$

Part (b) Step 2: Explanation

The balanced equation for the neutralization of $\mathrm{HCl}\left(aq\right)\text{ and }\mathrm{Fe}\left(\mathrm{OH}{)}_3\right(s)$ is,

$3\mathrm{HCl}\left(aq\right)+\mathrm{Fe}\left(\mathrm{OH}{)}_3\right(s)\to 3{\mathrm{H}}_2\mathrm{O}(l)+{\mathrm{FeCl}}_3(aq)$

The reaction of HCL with $Fe{\left(OH\right)}_3$ gives water $H_{2}O$ and ferric chloride salt $FeC{l}_3$.

Part (c) Step 1: Given Information

Write a balanced equation for the neutralization of-

${\mathrm{H}}_2{\mathrm{CO}}_3\left(aq\right)\text{ and }\mathrm{Mg}\left(\mathrm{OH}{)}_2\right(s)$

Part (c) Step 2: Explanation

The balanced equation for the neutralization of ${\mathrm{H}}_2{\mathrm{CO}}_3\left(aq\right)\text{ and }\mathrm{Mg}\left(\mathrm{OH}{)}_2\right(s)$ is,

${\mathrm{H}}_2{\mathrm{CO}}_3\left(aq\right)+\mathrm{Mg}\left(\mathrm{OH}{)}_2\right(s)\to {\mathrm{H}}_2\mathrm{O}(l)+{\mathrm{MgCO}}_3(aq)$

The reaction of $H_{2}C{O}_3$ with $Mg{\left(OH\right)}_2$ gives water $H_{2}O$ and magnesium carbonate salt $MgC{O}_3$