Q. 9.90

Question

Indicate whether each of the following ionic compounds is soluble or insoluble in water: $(9.3)$

a. ${CuCO}_{3}$

b. $F e O$

c. $M g_{3} {(P O_{4})}_{2}$

d. ${(N H_{4})}_{2} S O_{4}$

e. $N a H C O_{3}$

Step-by-Step Solution

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Answer

Part a) As a consequence, $C u C O_{3}$ is water insoluble.

Part b) As a corollary, $F e O$ is water insoluble.

Part c) As a function, $M g_{3} {(P O_{4})}_{2}$ is water insoluble.

Part d) As a response, ${(N H_{4})}_{2} S O_{4}$ is water soluble.

Part e) As just a result, $N a H C O_{3}$ is water soluble.

1Step 1: Introduction.(Part a)

A mixture is a compound that is made by chemically joining two or more substances elements combined. The sort of connection that holds elements of a compound together could be varied.

2Step 2: Given data (a).

(a) The solubility criteria are used to determine if an ionic chemical is soluble in water. The following table summarises the limiting reagent for cationic solids in water:

Table: Water Solubility Laws for Neutral Solids

3Step 3: Explanation (a).

$C u C O_{3}$ is comprised of the ions $C u^{2 +} a n d C {O_{3}}^{2 -} .$ Unless the salt includes the cations $L i^{+}, N a^{+}, K^{+} o r N H^{+},$ a salt having $C {O_{3}}^{2 -}$ is water insoluble. The $C u C O_{3}$ is immiscible with water.

4Step 4: Given data (b).

$F e O$ is mainly composed of the ions $F e^{2 +} a n d O^{2 -} .$

5Step 5: Explanation (b).

b) Because $F e O$ lacks a soluble positive charge, an iron salt including an $O^{2 -}$ ion will indeed be sticky. As a result, $F e O$ is water insoluble.

6Step 6: Given data (c).

The ions $M g^{2 +} a n d P {O_{4}}^{3 -}$ try to compensate $M g_{3} {(P O_{4})}_{2}$ .

7Step 7: Explanation (c).

Except if the solution includes the metal ions $L i^{+}, N a^{+}, K^{+} o r N H^{+}$ , a compound possessing $P {O_{4}}^{3 -}$ is insoluble in water. As a result, $M g_{3} {(P O_{4})}_{2}$ is water insoluble.