Q. 9.25 - An Introduction to General, Organic, and Biological Chemistry

Question

Determine whether each of the following solutions will be saturated or unsaturated at ${20}^{\circ }C$ :

a. adding $25 g$ of $KCl$ to $100 g$ of $H_{2}O$ 

b. adding $11 g$ of $NaN{O}_3$ to $25 g$ of $H_{2}O$

c. adding $400 g$ of sugar to $125 g$ of $H_{2}O$

Step-by-Step Solution

Answer

(part a) The following solution $25 g of KCl to 100 g of H_{2}O$ is an unsaturated solution.

(part b) The following solution $11 g of NaN{O}_3 to 25 g of H_{2}O$ represents an unsaturated solution.

(part c) The following solution $400 g of sugar to 125 g of H_{2}O$ and it forms the saturated solution.

Step1: Introduction (part a).

Saturated solution: At a specific temperature, the solution cannot dissolve any further solute.

Unsaturated solution: At a specific temperature, a solution can dissolve more solute.

Step2: Given Information (part a).

Given:

$25 g of KCl to 100 g of H_{2}O$

Step3: Explanation (part a).

Adding $25 g of KCl$ to $100 g$ of water symbolizes an unsaturated solution because it can dissolve up to $34 g of KCl$ in $100 g$ of water at ${20}^{\circ }C.$

Step4: Given Information (part b).

Given:

$11 g of NaN{O}_3 to 25 g of H_{2}O$

Step5: Explanation (part b).

At ${20}^{\circ }C, 88 g$ of sodium nitrate melts in $100 g$ of water, and at this temperature, $22 g$ of sodium nitrate could indeed dissipate in $25 g$ of water. So, if $11 g$of sodium nitrate is blended with $25 g$ of water, the result is an unsaturated solution.

Step6: Given Information (part c).

Given:

$400 g of sugar to 125 g of H_{2}O$

Step7: Explanation (part c).

At ${20}^{\circ }C, 100 g$ of water could really dissipate $203.9 g$ of sugar, so $125 g$ of water could disintegrate $253 mg$ of sugar. Adding$400 g$ of sugar to $125 g$ of water at a temperature will result in a saturated solution.