Q 81 - Intermediate Algebra

Question

Jackie has been offered

positions by two cable companies.

The first company pays a salary of

$\backslash (14,000$ plus a commission of $\backslash )100$

for each cable package sold. The

second pays a salary of $\backslash (20,000$

plus a commission of $\backslash )25$ for each

cable package sold. How many

cable packages would need to be

sold to make the total pay the

same?

Step-by-Step Solution

Answer

We need $80$ cable packages

Step 1. Given

Let the number of cable packages be $x$

First company gives salary $\$14,000$ with a commission of $\$100$

Second company gives salary $\$20,000$ with a commission of $\$25$

Step 2. Calculation

For the first company $\$14,000+\$100x$

For the second company $\$20,000+\$25x$

According to the question, 

$$\begin{gathered} \$14,000+\$100x=\$20,000+\$25x \\ 100x-25x=20000-14000 \\ 75x=6000 \\ x=80 \end{gathered}$$

Therefore we need $80$ cable packages.