Q 80 - Intermediate Algebra

Question

Maxim has been offered

positions by two car companies.

The first company pays a salary of

$\backslash (10,000$ plus a commission of

$\backslash )1000$ for each car sold. The

second pays a salary of $\backslash (20,000$

plus a commission of $\backslash )500$ for

each car sold. How many cars

would need to be sold to make the

total pay the same?

Step-by-Step Solution

Answer

We need total $20$ cars

Step 1. Given

First company gives $\$10,000$ salary with a commission of $\$1000$

Second company gives $\$20,000$ salary with a commission of $\$500$

Step 2. Calculation

Let the number of cars is $x$

For the first company the pay is $\$10,000+\$1000x$

For second company the pay is $\$20,000+\$500x$

According to question both pays are same

$$\begin{gathered} \$10,000+\$1000x=\$20,000+\$500x \\ 1000x-500x=20000-10000 \\ 500x=10000 \\ x=20 \end{gathered}$$

Therefore we need $20$ cars.