Q 65.
Question
Let S be a subset of or . Prove that a set S is open if and only if
Step-by-Step Solution
Verified Answer
It is proved that a set S is open if and only if .
1Step 1. Given information.
We have given S be a subset of .
2Step 2: Prove the given statement.
We have given S be a subset of .
Assume an element x' such that .where S is an open set.
A set is said to be open if for every element of it, there exists an open disk or ball D, such that
This would mean that 'x' does not belong to the boundary of S .
Thus, there is no common element between and is .
In another case, consider S is not an open set.
Thus, the set or is non-empty.
Combining the two proofs, it is proved that, "that the set is open if and only if "
Other exercises in this chapter
Q 63.
Prove Theorem 12.10. That is, show that see=s when S is a subset of R2or R3.
View solution Q 64.
Prove that if S is a closed subset of R2 or R3, then Se is an open set. This is Theorem 12.12
View solution Q 66.
Let S be a subset of R2 or R3. Prove that a set S is closed if and only if ∂S⊆S.
View solution Q 67.
Let S be a subset of R2 or R3. Prove that ∂S=∂Sc
View solution