Q 63.

Question

Prove Theorem 12.10. That is, show that see=s when S is a subset of R2or R3

Step-by-Step Solution

Verified
Answer

The theorem is proved "If S is the subset of R2 or R3,then see=s

1Step 1. Given information.

We have given subset see=s

2Step 2: To find the complement of S

If S is the subset of S2 then the complement of S is

Se=x,yR2:x,ys

Now the complement of Se is :

see=x,yR2:x,ySe

According to the definition of complement of a set, it is clear that elements which are included in a set are not included in its complement. Similarly, the elements which are not included in the complement must be included in the original set. 

Thus, if x,yse then x,ys

Therefore, 

see=x,yR2:x,yssee=s