Q. 6.153 - An Introduction to General, Organic, and Biological Chemistry

Question

Complete the Lewis structure for each of the following: $(6.6)$

a.

b. 

c.

d. 

Step-by-Step Solution

Answer

a. The Lewis structure is .

b. The Lewis structure is  .

c. The Lewis structure is  .

d. The Lewis structure is  .

Part (a) step 1: Given Information

We need to complete the given Lewis structure. 

Part (a) step 2: Simplify

According to the question the valence electrons of each element in the molecule.

The element $H$ has $1$ a valence electron.

The element $C$ has $4$ valence electrons.

The element $N$ has $5$ valence electron.

The element $O$ has $6$ valence electron.

In $H$ molecule is already participating in one bond. So, the number of valance electron left to fill is $0$.

In $N$ molecule is participating in $3$ bond. So, the number of valance electron left to fill is $2$.

In $C$ molecule is participating in $3$ bond. In which one is double bond.  So, the number of valance electrons left to fill is $0$.

In $O$ molecule is  participating in $2$ bond. So, the number of valance electron left to fill is $4$.

Hence, the complete Lewis structure is :

Part (b) step 1: Given Information

We need to complete the given Lewis structure. 

Part (b) step 2: Simplify

According to the question the valence electrons of each element in the molecule.

The $H$element  has $1$ valence electron.

The $C$ element  has $4$ valence electron.

The $N$ element  has $5$ valence electron.

The $Cl$ element  has $7$ valence electron.

In  $H$molecule is participating in one bond. So, the number of valance electron left to fill is $0$.

In $Cl$ molecule is participating in one bond. So, the number of valance electron left to fill is $6$.

In one of the $C$ molecule is  participating in $4$  bond. So, the number of valance electrons left to fill is $0$.

The another $C$ is participating in $2$ bond in which one is triple bond with $N$. So , the number

of valance electrons left to fill is $0$.

Hence, the complete Lewis structure is :

Part (c) step 1: Given Information

We need to complete the given Lewis structure.

Part (c) step 2: Simplify

According to the question the valence electrons of each element in the molecule.

The $H$ element  has $1$ valence electron.

The $N$ element  has $5$ valence electron.

In $H$ molecule is participating in one bond. So, the number of valance electrons left to fill is $0$.

In  $N$ molecule is participating in a $2$bond in which one is double bond. So, the number of valance electrons left to fill is $3$ .

Hence, the complete Lewis structure is :

Part (d) step 1: Given Information

We need to complete the given Lewis structure. 

Part (d) step 2: Simplify

According to the question the valence electrons of each element in the molecule.

The element $H$ has $1$ valence electron.

The element $Cl$ has $7$ valence electron.

The element $O$ has $6$ valence electron.

The element $C$ has $4$ valence electron.

In  $H$ molecule is participating in one bond. So, the number of valance electrons left to fill is $0$.

In $Cl$ molecule is participating in one bond. So, the number of valance electron left to fill is $6$.

In one of the  $C$ molecule is participating in $4$ bond. So, the number of valance electrons left to fill is $0$.

In another $C$ molecule  is participating in  $3$ bonds in which one is a double bond.

In  $O$ molecule is participating in double bond. with $C$.

The another $O$ molecule has $2$ single bond.

Hence, the complete Lewis structure is :