Q. 6.133 - An Introduction to General, Organic, and Biological Chemistry

Question

Show the dipole arrow for each of the following bonds: $(6.7)$

a. $Si-Cl$

b. $C-N$

c. $F-Cl$

d. $C-F$

e. $N-O$

Step-by-Step Solution

Answer

a. The dipole arrow of $Si-Cl$ is .

b. The dipole arrow of  $C-N$ is.

c. The dipole arrow of  $F-Cl$ is .

d. The dipole arrow of  $C-F$ is.

e. The dipole arrow of  $N-O$ is.

Part (a) step 1: Given Information

We need to find the dipole arrow of  $Si-Cl$.

Part (a) step 2: Explanation

Here,

Consider bond is $Si-Cl$.

The electronegativity of $Si$ is $1.8$ and the electronegativity of $Cl$ is $3.0$. So, the arrow should be pointing towards $Cl$.

Here, the dipole arrow is shown below.

Part (b) step 1: Given Information

We need to find the dipole arrow of  $C-N$.

Part (b) step 2: Explanation

Here,

Consider bond is $C-N$.

The electronegativity of $C$ is $2.5$ and the electronegativity of $N$ is $3.0$. So, the arrow should be pointing towards $N$.

Here , the dipole arrow is shown below.

Part (c) step 1: Given Information

We need to find the dipole arrow of  $F-Cl$.

Part (c) step 2: Explanation

Here,

Consider bond is $F-Cl$.

The electronegativity of $F$ is $4.0$ and the electronegativity of $Cl$ is $3.0$ . So, the arrow should be pointing towards $F$.

Here , the dipole arrow is shown below.

Part (d) step 1: Given Information

We need to find the dipole arrow of $C-F$. 

Part (d) step 2: Explanation

Here,

Consider bond is $C-F$.

The electronegativity of $C$ is $2.5$ and the electronegativity of $F$ is $4.0$ . So, the arrow should be pointing towards $F$.

Here, the dipole arrow is shown below.

Part (e) step 1: Given Information

We need to find the dipole arrow of $N-O$.  

Part (e) step 2: Explanation

Here,

Consider bond is $N-O$ .

The electronegativity of $N$  is $3.0$ and the electronegativity of $O$ is $3.5$  . So, the arrow should be pointing towards $O$.

Here, the dipole arrow is shown below.