Q. 6.130 - An Introduction to General, Organic, and Biological Chemistry

Question

Use the periodic table to arrange the following atoms in order of increasing electronegativity: ($6.7$) 

a. data-custom-editor="chemistry" $\mathrm{Cl}, \mathrm{Br}, \mathrm{Se}$ 

b. data-custom-editor="chemistry" $\mathrm{Na}, \mathrm{Cs}, \mathrm{O}, \mathrm{S}$

c. data-custom-editor="chemistry" $\mathrm{O}, \mathrm{F}, \mathrm{B}, \mathrm{Li}$

Step-by-Step Solution

Answer

(a) The increasing order of electronegativity is $\mathrm{Se}<\mathrm{Br}<\mathrm{Cl}$

(b) The increasing order of electronegativity is $\mathrm{Cs}<\mathrm{Na}<\mathrm{S}<\mathrm{O}$

(c) The increasing order of electronegativity is $\mathrm{Li}<\mathrm{B}<\mathrm{O}<\mathrm{F}$

Part (a) Step 1: Given information

We need to find the increasing order of electronegativity

Part (a) Step 2: Explanation

We know that

Electronegativity increases as we go top-right 

Therefore, increasing order of electronegativity is,

$\mathrm{Se}<\mathrm{Br}<\mathrm{Cl}$

Part (b) Step 1: Given information

We need to find increasing order of electronegativity

Part (b) Step 2: Explanation

We know that

Electronegativity increases as we go top-right 

Therefore, increasing order of electronegativity is,

$\mathrm{Cs}<\mathrm{Na}<\mathrm{S}<\mathrm{O}$

Part (c) Step 1: Given information

We need to find the increasing order of electronegativity

Part (c) Step 2: Explanation

We know that,

$\mathrm{O}, \mathrm{F}, \mathrm{B}, \mathrm{Li}$ all lie in same period and different group

And electronegativity increases as we move left to right in a period 

Therefore, increasing order of electronegativity is,

$\mathrm{Li}<\mathrm{B}<\mathrm{O}<\mathrm{F}$