Q. 6.128 - An Introduction to General, Organic, and Biological Chemistry

Question

Draw the Lewis structure for each of the following: ($6.6$)

a. data-custom-editor="chemistry" ${\mathrm{H}}_3{\mathrm{COCH}}_3$(the atoms are in the order data-custom-editor="chemistry" $\mathrm{C} \mathrm{O} \mathrm{C}$)

b. data-custom-editor="chemistry" ${\mathrm{HNO}}_2$ (the atoms are in the order data-custom-editor="chemistry" $\mathrm{HONO}$)

c. $OB{r}_2$

Step-by-Step Solution

Answer

(a) The Lewis structure of ${\mathrm{H}}_3{\mathrm{COCH}}_3$ is

(b) The Lewis structure of ${\mathrm{HNO}}_2$ is

(c) The Lewis structure of ${\mathrm{OBr}}_2$ is

Part (a) Step 1: Given Information

We need to find the Lewis structure of ${\mathrm{H}}_3{\mathrm{COCH}}_3$

Part (a) Step 2: Explanation

We know that, 

$\mathrm{H}$ belongs to group one, meaning it possesses one valence electrons.

$\mathrm{O}$ belongs to group six, meaning it possesses six valence electrons.

$\mathrm{C}$ belongs to group four, meaning it possesses four valence electrons.

As a result, the molecule has a total of $20$ valence electrons.

$\mathrm{O}$ is the center atom

As a result, the molecule's Lewis structure is

Part (b) Step 1: Given Information

We need to find the Lewis structure of ${\mathrm{HNO}}_2$

Part (b) Step 2: Explanation

We know that, 

$\mathrm{H}$ belongs to group one, meaning it possesses one valence electrons.

$\mathrm{O}$ belongs to group six, meaning it possesses six valence electrons.

$\mathrm{N}$ belongs to group five, meaning it possesses five valence electrons.

As a result, the molecule has a total of $18$ valence electrons.

As a result, the molecule's Lewis structure is

Part (c) Step 1: Given Information

We need to find the Lewis structure of ${\mathrm{OBr}}_2$

Part (c) Step 2: Explanation

We know that, 

$\mathrm{Br}$ belongs to group seven, meaning it possesses seven valence electrons.

$\mathrm{O}$ belongs to group six, meaning it possesses six valence electrons.

As a result, the molecule has a total of $20$ valence electrons.

$\mathrm{O}$ is the center atom

As a result, the molecule's Lewis structure is