Q. 6.121 - An Introduction to General, Organic, and Biological Chemistry

Question

Classify each of the following as ionic or molecular, and give its name: (6.3,6.5)

a. $FeC{l}_3$ b. $N{a}_{2}S{O}_4$ c. $N{O}_2$ d. $R{b}_{2}S$ e. $P{F}_5$ f. $C{F}_4$

Step-by-Step Solution

Answer

(a) $FeC{l}_3$ is ionic and name of ionic compound is Ferric chloride.

(b) $N{a}_{2}S{O}_4$ is ionic and name of ionic compound is Sodium sulfate.

(c) $N{O}_2$ is molecular and name of molecular compound is nitrogen dioxide.

(d) $R{b}_{2}S$is ionic and name of ionic compound is Rubidium sulfate.

(e) $P{F}_5$ is molecular and name of molecular compound is Phosphorus pentafluoride.

(f) $C{F}_4$ is molecular and name of molecular compound is Carbon tetrafluoride.

Part(a) Step 1: Given information

We have been given,

Fe and Cl are the symbol used in this formula.

Part(a) Step 2: Explanation

The $FeC{l}_3$ is ionic compound. As the compound contain iron which is metal. all ionic compound contain metal.

Identify the cation and anion. The cation is $F{e}^{3+}$ and anion $C{l}^{-}$.

The cation $F{e}^{3+}$is iron. and the anion $C{l}^{-}$is chloride.

As per rule write the name of cation first and anion second,

So, Ionic compound name is Ferric Chloride.

Part(b) Step 1: Given information

We have been given,

Na , S and O are the symbol used in this formula.

Part(b) Step 2: Explanation

Now, $N{a}_{2}S{O}_4$is Ionic compound, As the compound contain Sodium which is metal. all ionic compound contain metal.

Now, Na = Sodium , S = Sulphur and O = Oxygen,

As there are $2$molecule of sodium and $1$molecule of Sulphur and $4$molecule of Oxygen,

Hence the name of given ionic compound is Sodium sulfate.

Part(c) Step 1: Given information

We have been given,

N and O symbol used in this formula.

Part(c) Step 2: Explanation

Now, $N{O}_2$ is molecular compound, because the connection is created by the sharing of electrons between one nitrogen and two oxygen atoms.

As there are $1$molecule of nitrogen and $2$molecule of Oxygen,

The name of given molecular compound is nitrogen dioxide. 

Part(d) Step 1: Given information

We have been given,

Rb and S symbols are used in this formula.

Part(d) Step 2: Explanation

Now, $R{b}_{2}S$ is Ionic compound. As the compound contain  metal. all ionic compound contain metal.

As there are $2$molecule of Rubidium and $1$of Sulphur,

The name of Ionic compound is  Rubidium sulfate. 

Part(e) Step 1: Given information

We have been given,

P and F symbols used in this formula.

Part(e) Step 2: Explanation

Now, $P{F}_5$is molecular compound, Because their are two non metal.

As there are $1$ molecule of Phosphorus and $5$ molecule of fluorine,

The name of molecular compound $P{F}_5$ stands for Phosphorus pentafluoride.

Part(f) Step 1: Given information

We have been given,

C and F symbols are used in this formula.

Part(f) Step 2: Explanation

Now, $C{F}_4$ is molecular compound, Because both elements are nonmetals,

As there are $1$molecule of carbon and $4$molecule of Fluorine,

The name of given compound $C{F}_4$stands for carbon tetrafluoride