Q. 6.120 - An Introduction to General, Organic, and Biological Chemistry

Question

Write the formula for each of the following molecular compounds: $(6.5)$

a. silicon dioxide

b. carbon tetrabromide

c. diphosphorus tetraiodide

d. dinitrogen trioxide

Step-by-Step Solution

Answer

(a) silicon dioxide has the formula $Si{O}_2$.

(b) carbon tetrabromide has the formula $CB{r}_4$.

(c) diphosphorus tetraiodide has the formula $P_2{I}_4$.

(d) dinitrogen trioxide has the formula $N_2{O}_3$.

Part(a) Step 1: Given information

We have to find out the formula of silicon dioxide.

Part(a) Step 2: Explanation

Now, silicon = Si and oxide = O,

As there are $1$molecule of silicon and $2$ molecule of Oxygen,

And valency Si$=4$ and O$=2$,

Hence formula $Si{O}_2$.

Part(b) Step 1: Given information

We have to find out the formula of carbon tetrabromide.

Part(b) Step 2: Explanation

Now, Carbon = C and Bromide = Br,

As there are $1$molecule of carbon and $4$ molecule of bromine.

And valency C$=4$ and Br$=1$,

Hence formula $CB{r}_4$.

Part(c) Step 1: Given information

We have to find out the formula of diphosphorus tetraiodide.

Part(c) Step 2: Explanation

Now, Phosphorus = P and Iodide = I,

As there are $2$ molecule of phosphorus and $4$molecule of iodide,

And valency P$=3$ and I$=-1$,

Hence formula $P_2{I}_4$.

Part(d) Step 1: Given information

We have to find out the formula of dinitrogen trioxide.

Part(d) Step 2: Explanation

Now, Nitrogen = N and oxide = O,

As there are $2$ molecule of nitrogen and $3$molecule of oxygen,

And valency N$=3$ and O$=2$,

Hence formula $N_2{O}_3$.