Q 5 TB - Calculus

Question

To find the equation of circle in ${\mathrm{ℝ}}^2$ having center at (3, 6) and is tangent to x axis.

Step-by-Step Solution

Answer

The required equation is ${(x-3)}^2+{(y-6)}^2=9$

Given information

The circle is in ${\mathrm{ℝ}}^2$, center at (3, 6) and is tangent to y axis.

Finding the equation

The circle is tangent to y axis so radius will be x coordinate of center.

The required equation is:

${(x-3)}^2+{(y-6)}^2=9$