Q 4 TB - Calculus

Question

To find the equation of a circle in ${\mathrm{ℝ}}^2$with center (3, 6) and is tangent to x - axis.

Step-by-Step Solution

Answer

The required equation is ${(x-3)}^2+{(y-6)}^2=36$

Given information

Given that the circle has center at (3, 6) and is tangent to x axis.

Finding the equation of circle

The circle is tangent to x axis, so radius is y coordinate of center.

The equation of circle is:

${(x-3)}^2+{(y-6)}^2=36$