Q. 43

Question

In Problems 35–58, graph each function. Be sure to label key points and show at least two cycles. Use the graph to determine the domain and the range of each function.  

y=2sin12x

Step-by-Step Solution

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Answer

The graph of y=2sin12x:


1Step 1. Given information

The function to be plotted is:

y=2sin12x

2Step 2. Determine the amplitude and period of the sinusoidal function.

By comparing the given function y=2sin12x with y=Asinωx


We get amplitude: A=2

Time period : T=2πωT=2π12T=4π

The graph will lie between -2 and 2 on the y-axis. One cycle begins at  x=0 and ends at x=4π.

3Step 3. : Divide the interval into four subintervals of the same length.

Divide the interval 0,4π into four subintervals,

each of length:4π4=π

The x-coordinates of the five key points are :

The first x-coordinate is 0

second x-coordinate is: 0+π=π

Third x-coordinate is: π+π=2π

Fourth x-coordinate is: 2π+π=3π

Fifth x-coordinate is:3π+π=4π

These values represent the x-coordinates of the five key points on the graph. 

4Step 4. Use the endpoints of these subintervals to obtain five key points on the graph.

Since y=2sin12x

 Hence, multiply the y-coordinates of the five key points for y=sinx  by 2

 The five key points on the graph are 

0,0,π,2,2π,0,3π,2,4π,0.

5Step 5. Plot the five key points and draw a sinusoidal graph to obtain the graph of one cycle. Extend the graph in each direction to make it complete.


Plot the five key points obtained in Step 4 and fill in the graph. Extend the graph in each direction to obtain the complete graph. Notice that additional key points appear every π radian.




6Step 6. To find domain and range of the function

As we can see that the value of x is set of all real number.

So domain is -,

The y- value of the function in the graph lies from -2 to 2

So the range of the function is -2,2