Q. 41

Question

In Problems 35–58, graph each function. Be sure to label key points and show at least two cycles. Use the graph to determine the domain and the range of each function. 

y=sin-2x

Step-by-Step Solution

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Answer

The graph of the function is:


  • The domain is: -,
  • Range is: -1,1
1Step 1. Given information

The function to be plotted is:

y=sin-2x

y=-sin2x, since this is an odd function.

2Step 2. Determine the amplitude and period of the sinusoidal function.

By comparing the given function y=-sin2x

with y=Asinωx

we get amplitude: A=-1=1

Time period : T=2πωT=2π2T=π

The graph will lie  between -1 and 1 on the y-axis. One cycle begins at  x=0 and ends at x=π

3Step 3. : Divide the interval 0 , π into four subintervals of the same length.

Each x-coordinate will have interval: π4

The first x-coordinate is 0

Second x-coordinate is 0+π4=π4

Third x-coordinate is π4+π4=π2

Fourth x-coordinate is π2+π4=3π4

Fifth x-coordinate is 3π4+π4=π

Five x-coordinates are:

0,π4,π2,3π4,π

4Step 4. Use the endpoints of these subintervals to obtain five key points on the graph.

Since y=-sin2x

 multiply the y-coordinates of  the five key points for sinx  by -1.

 The five key points on the graph are:

0,0,π4,-1,π2,0,3π4,1,π,0

5Step 5. Plot the five key points and draw a sinusoidal graph to obtain the graph of one cycle. Extend the graph in each direction to make it complete.

Plot the five key points obtained in Step 4 and fill in the graph . Extend the graph in each direction to obtain the complete graph . Notice that additional key points appear every  π4radian.

 


6Step 6. To find domain and range of the function

As we can see that the value of x is set of all real number.

So domain is -,.

The y- value of the function in the graph lies from -1 to 1.

So range of the function is -1,1.