Q. 4.114

Question

There are four naturally occurring isotopes of Iron: F2654e, F2656e, F2657e and F2658e

a. How many protons, neutrons, and electrons are in F2658e?

b. What is the most abundant isotope in an Iron sample?

c. How many neutrons are in F2657e?

d. Why don't any of the isotopes of Iron have the atomic mass of 55.85 amu listed on the periodic table?

Step-by-Step Solution

Verified
Answer

a. In F2658e the number of protons and electrons is 26 and the number of neutrons is 32.

b. The F2656e is the most abundant isotope.

c. The number of neutrons in F2657e is 31.

d. The isotopes of Strontium with mass 55.85 amu is not listed in the periodic table because of the weighted average.

1Part (a) Step 1: Given Information

We need to find the number of protons, neutrons, and electrons in F2658e.

2Part (a) Step 2: Simplify

Using the basic representation of an atom, that is XZA in which A is the mass number, Z is the atomic number and X is the atom.

For F2658e, the number of protons and electrons is 26

And neutrons is A-Z, i.e.

Neutrons=58-26Neutrons=32

3Part (b) Step 1: Given Information

We need to find the abundant isotope in the Iron sample.

4Part (b) Step 2: Explanation

To conclude the most prevalent Iron isotope. First, compare the isotopes to the weighted average in the periodic table. As the Iron has a weight average of 55.85 amu, the most prevalent Iron isotope is F2656e.

5Part (c) Step 1: Given Information

We need to find the number of neutrons in F2657e.

6Part (c) Step 2: Calculation

Calculating the number of neutrons in F2657e.

Neutrons=A-ZNeutrons=57-26Neutrons=31

7Part (d) Step 1: Given Information

We need to explain the reason for the isotopes of Iron with an atomic mass of 55.85 amu is not listed on the table.

8Part (d) Step 2: Explanation

The isotopes of the Iron don't have an atomic mass of  55.85 amu due to the said value being the weighted average of the atomic masses of all of its existing isotopes.