Q. 4.107 - An Introduction to General, Organic, and Biological Chemistry

Question

Write the group number and the electron arrangement for each of the following: $(4.6)$

a. Oxygen

b. Sodium

c. Neon

d. Boron

Step-by-Step Solution

Answer

a. The group number is $6A$ and the electron arrangement is $2,6$.

b. The group number is $1A$and the electron arrangement is $2,8,1$.

c. The group number is $8A$ and  the electron arrangement is $2,8$.

d. The group number is $3A$ and the electron arrangement is $2,3$ .

Part (a) step 1: Given Information

We need to find the group number and the electron arrangement. 

Part (a) step 2: Explanation

According to the periodic table, Oxygen belongs in Group $6A$.

It is started in the periodic table that it has an atomic number of  $8$. For an  electron arrangement, the first two electrons would fill the first energy level. Then, the remaining six electrons would occupy the second energy level. So Oxygen  $2,6$.

Part (b) step 1: Given Information

We need to find the group number and the electron arrangement. 

Part (b) step 2: Explanation

According to the periodic table, Sodium belongs in Group $1A$.

It is started in the periodic table that it has an atomic number of  $11$. For an electron arrangement, the first two electrons would fill the first energy level. Then, the order of eight electrons would fill the second energy level. The single remaining electrons would occupy the third energy level. So, Sodium $2,8,1$.

Part (c) step 1: Given Information

We need to find the group number and the electron arrangement. 

Part (c) step 2: Explanation

According to the periodic table, Neon belongs in Group $8A$.

It is started in the periodic table that it has an atomic number of  $10$. For an electron arrangement, the first two electrons would fill the first energy level. Then, the remaining eight electrons would fill the second energy level. So  Neon $2,8$.

Part (d) step 1: Given Information

We need to find the group number and the electron arrangement. 

Part (d) step 2: Explanation

According to the periodic table, Boron belongs in Group $3A$.

It is started in the periodic table that it has an atomic number of  $5$. For an electron arrangement, the first two electrons would fill the first energy level. Then, the remaining three electrons would fill the second energy level. So  Boron $2,3$.