Q. 4.100 - An Introduction to General, Organic, and Biological Chemistry

Question

For the following atoms, determine the number of protons, neutrons, and electrons:$(4.4 , 4.5)$

a. ${}_{80}{}^{202}Hg$

b. ${}_{53}{}^{127}I$

c. ${}_{35}{}^{75}Br$

d. ${}_{55}{}^{133}Cs$

e. ${}_{78}{}^{195}Pt$

Step-by-Step Solution

Answer

a. The number of electrons is $80$, neutrons is $122$, and protons is $80$ in ${}_{80}{}^{202}Hg$.

b. The number of electrons is  $53$ , neutrons is $74$, and protons is $53$ in ${}_{53}{}^{127}I$.

c. The number of electrons is $35$  , neutrons is $40$, and protons is  $35$ in ${}_{35}{}^{75}Br$.

d. The number of electrons is  $55$ , neutrons is  $78$ and protons is  $55$ in ${}_{55}{}^{133}Cs$.

e. The number of electrons is   $78$ , neutrons is   $117$and protons is   $78$ in ${}_{78}{}^{195}Pt$.

Part (a) step 1: Given Information

We need to find the number of electrons, protons, and neutrons,   in ${}_{80}{}^{202}Hg$.

Part (a) step 2: Simplify

Consider: ${}_{80}{}^{202}Hg$

The standard form atom is:- ${}_z{}^{A}X$

A is the mass number of atom 

Z is the number of the element 

Number of  protons in element (P) = Atomic number = Z =Number of electron (e)

Number of neutrons =(N) Mass number (A) = $P+N$

$N=A-P=A-Z$

Here, Z= $80$ and , A=$202$

Then e= $80$

P=$80$

N=$202-80=122$

Part (b) step 1: Given Information

We need to find the number of electrons, protons, and neutrons,   in ${}_{53}{}^{127}I$.

Part (b) step 2: Simplify

Consider: ${}_{53}{}^{127}I$

The standard form atom is:- ${}_z{}^{A}X$

A is the mass number of atom 

Z is the number of the element 

Number of  protons in element (P) = Atomic number = Z =Number of electron (e)

Number of neutrons =(N) Mass number (A) =$P+N$

$N=A-P=A-Z$

Here, Z= $53$ and A= $127$

Then,

e$=53$

p$=53$

N$=127-53=74$

Part (c) step 1: Given Information

We need to find the number of electrons, protons, and neutrons,  ${}_{35}{}^{75}Br$.

Part (c) step 2: Simplify

Consider: ${}_{35}{}^{75}Br$

The standard form atom is:- ${}_z{}^{A}X$

A is the mass number of atom 

Z is the number of the element 

Number of  protons in element (P) = Atomic number = Z =Number of electron (e)

Number of neutrons =(N) Mass number (A) =$P+N$

$N=A-P=A-Z$

Here Z$=35$ and A$=75$

Then,

e$=35$

p$=35$

N$=75-35=40$

Part (d) step 1: Given Information

We need to find the number of electrons, protons, and neutrons,   in ${}_{55}{}^{133}Cs$.

Part (d) step 2: Simplify

Consider: ${}_{55}{}^{133}Cs$

The standard form atom is:- ${}_z{}^{A}X$

A is the mass number of atom 

Z is the number of the element 

Number of  protons in element (P) = Atomic number = Z =Number of electron (e)

Number of neutrons =(N) Mass number (A) =$P+N$

$N=A-P=A-Z$

Here, Z$=55$ and A$=133$

Then,

e$=55$

p$=55$

N$=133-55=78$

Part (e) step 1: Given Information

We need to find the number of electrons, protons, and neutrons,   in ${}_{78}{}^{195}Pt$.

Part (e) step 2: Simplify

Consider: ${}_{78}{}^{195}Pt$

The standard form atom is:- ${}_z{}^{A}X$

A is the mass number of atom 

Z is the number of the element 

Number of  protons in element (P) = Atomic number = Z =Number of electron (e)

Number of neutrons =(N) Mass number (A) $=P+N$

$N=A-P=A-Z$

Here, Z $=78$ and A$=195$

Then,

e$=78$

p$=78$

N$=195-78=117$