Q. 290 - Intermediate Algebra

Question

In the following exercises, divide the monomials.

$\frac{18a^4{b}^8}{-27a^9{b}^5}$

Step-by-Step Solution

Answer

The required answer is $-\frac{2b^3}{3a^5}$.

Step 1. Given Information

Given expression: $\frac{18a^4{b}^8}{-27a^9{b}^5}$

Step 2. Calculation

We have the expression

$\frac{18a^4{b}^8}{-27a^9{b}^5}$

$=\frac{18}{-27}·\frac{a^4}{a^9}·\frac{b^8}{b^5}$           write using fraction multiplication

$=\frac{2}{-3}·\frac{1}{a^5}·b^3$               simplify and using quotient property

$=-\frac{2b^3}{3a^5}$                   multiply