290. - Intermediate Algebra

Question

$\frac{18a^{4 }{b}^8}{-27a^9 b^5}$

Step-by-Step Solution

Answer

$\frac{-2b^3}{3a^5}$

Step 1

• Use fraction multiplication. 

Step 2

Use quotient property to simplify.

$$\begin{gathered} =\frac{18}{-27}.\frac{a^4}{a^9}.\frac{b^8}{b^5} \\ =\frac{-2}{3}.\frac{1}{a^5}.63 \end{gathered}$$

Step 3

Multiply the results to get the answer.

$=\frac{-2b^3}{3a^5}$