Q. 22

Question

In Problems 19–26, apply the methods of this and the previous section to graph each function. Be sure to label key points and show at least two periods.

y=12sec(3x-π)

Step-by-Step Solution

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Answer

The graph of the function y=12sec(3x-π) is:


1Step 1. Given

The function y=12sec(3x-π)

To graph the function with at least two cycles.

2Step 2. Find the amplitude, period and phase shift.

Compare the given function y=12sec(3(x-π3)) with y=A sin (ωx-ϕ)+B

No amplitude

Period, 2πω=2π3

Phase shift, ϕω=π3

3Step 3. Determine x - coordinates

One cycle begins at x=ϕω(π3) and ends at

x=ϕω+2πω  =π3+2π3  =π

To find the five key points, divide the interval (π3,π) into four sub intervals, each of length 2π3÷4=π6

π3+π6=π2

π2+π6=2π3

2π3+π6=5π6

5π6+π6=π

The x-coordinates are π3,π2,2π3,5π6,π

4Step 4. Determine the key points

Use these values of x to determine the key points on the graph:

The key points include (π3,12),(-π3,12),(2π3,-12),(-2π3,-12),(π,12)

5Step 5. Sketch the graph

Plot these five points and fill in the graph of the function.