Q. 20

Question

In Problems 19–26, apply the methods of this and the previous section to graph each function. Be sure to label key points and show at least two periods.

y=12cot(2x-π)

Step-by-Step Solution

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Answer

The graph of the function y=12cot(2x-π) is:


1Step 1. Given

The function y=12cot(2x-π)

To graph the function with at least two cycles.

2Step 2. Find the amplitude, period and phase shift.

Compare the given function y=12cot(2(x-π2)) with y=A sin (ωx-ϕ)+B

No Amplitude

Period, T=2πω

               =π2

Phase shift, ϕω=π2

3Step 3. Determine x - coordinates

The graph of y=12cot(2(x-π2))

One cycle begins at x=ϕω(π2) and ends at x=ϕω+2πω

               =π2+π2=π

To find the five key points, divide the interval (π2,π)  into four sub intervals, each of length π2÷4=π8

π2+π8=5π8

5π8+π8=3π4

3π4+π8=7π8

7π8+π8=π

The x-coordinates are π2,5π8,3π4,7π8,π

4Step 4. Determine the key points.

Use these values of x to determine the key points on the graph:

The key points include (5π4,0),(3π4,0),(7π8,-12),(π8,12),(π4,0)

5Step 5. Sketch the graph.

Plot these five points and fill in the graph of the function.