Q. 14.15 - An Introduction to General, Organic, and Biological Chemistry

Question

Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:

a. acetic acid

b. pentanoic acid

Step-by-Step Solution

Answer

(part a)

(part b)

Step 1: Introduction (part a)

Carboxylic acids are weak acids that reduce basic by releasing hydrogen ion salts. To generate a methyl group having carbonyl group, either carboxyl group of both a carboxyl group is linked to both an aromatic rings. An methyl or benzyl component may engage to the carboxyl member. 

Step 2: Given Information (part a)

Formation seems to be a procedure wherein the carboxylic acid mixes with such an alcohol that make compounds in the presence of a catalyst.

Step 3: Explanation (part a)

(part a) The ester synthesized when acetic acid reactions using methane alconol has had the given reduced equation:

                           

                               

Step 4: Given Information (part b)

Formation seems to be a procedure wherein the carboxylic acid mixes with such an alcohol that make compounds in the presence of a catalyst.

Step 5: Explanation (part b)

(part b) The ester created when pentanoic acid combines using methyl alconol really does have the same reduced general formula: