Q. 14.12 - An Introduction to General, Organic, and Biological Chemistry

Question

Write the balanced chemical equation for the reaction of each of the following carboxylic acids with $KOH$ :

a. acetic acid

b. 2-methylbutanoic acid

c. 4-chlorobenzoic acid

Step-by-Step Solution

Answer

(part a)

(part b)

(part c)

Step 1: Introduction (part a)

An hydroxyl group seems to be a symmetrical proportion representation for which it charge and the group of particles to every constituent there in event are the same between the reactants and the products. In these other respects, its mass and voltage from both sides of both the response is comparable.  

Step 2: Given Information (part a)

The atoms of each element expression with each of the above carbonyl group in reactivity to $KOH.$

Step 3: Explanation (part a)

(part a) While carboxylic acids combine with only they conspire this is an unbelievable number when chlorine is generated.

Finally, acetic reacts chemically with phenol or quantities of water.

Step 4: Given Information (part b)

The atoms of each element expression with each of the above carbonyl group in reactivity to $KOH.$

Step 5: Explanation (part b)

(part b) While carboxylic acids combine with only they conspire  this is an unbelievable number when chlorine is generated. 

Finally, when $2$-methylbutanoic acid combines to,  $2$-methylbutanate oxalate or water is obtained.

           

Step 6: Given Information (part c)

The atoms of each element expression with each of the above carbonyl group in reactivity to $KOH.$

Step 7: Explanation (part c)

(part c) While carboxylic acids combine with only they conspire this is an unbelievable number when chlorine is generated. 

Finally, when $4$-chlorobenzoic acid combines into $4$-chloropotassium oxalate or water, -chloropotassium cortex or steam is created.