Q. 13.22 - An Introduction to General, Organic, and Biological Chemistry

Question

Identify each of the following as D or L enantiomer.

Step-by-Step Solution

Answer

Part(a) Arabinose is D enantiomer. 

Part(b) Sorbose is L enantiomer.

Part(c) Lyxose is  D enantiomer.

Part(d) Ribose is  L enantiomer.

Part (a) Step 1: Given Information

We need to identify Arabinose is D or L enantiomer.

Part (a) Step 2: Explanation

In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the right then the compound is a D-enantiomer.

In the given design of arabinose, the - OH bunch is appended to the base chiral focus and it focuses towards the right. In this way, it's a D-enantiomer.

Part (b) Step 1: Given Information

We need to identify sorbose is D or L enantiomer.

Part (b) Step 2: Explanation

 In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the left then the compound is an L-enantiomer.

In the given construction of sorbose, the - OH bunch is connected to the base chiral focus and it focuses towards the left. Hence, it's an L-enantiomer.

Part (c) Step 1: Given Information

We need to identify Lyxose is D or L  enantiomer.

Part (c) Step 2: Explanation

 In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the right then the compound is a D-enantiomer.

In the given design of lyxose, the - OH bunch is appended to the base chiral focus and it focuses towards the right. In this manner, it's a D-enantiomer.

Part (d) Step 1: Given Information

We need to identify Ribose is D or L enantiomer.

Part (d) Step 2: Explanation

 In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the left then the compound is an L-enantiomer.

In the given construction of Ribose, the - OH bunch is connected to the base chiral focus and it focuses towards the left. Hence, it's an L-enantiomer.