Q. 10.65 - An Introduction to General, Organic, and Biological Chemistry

Question

In Larry's esophageal pH  test, a pH value of  3.60 was recorded in the esophagus. What is the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$in his esophagus?

Step-by-Step Solution

Answer

The concentration of $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ is  $2.5\times {10}^{-4}\mathrm{M}$.

Step - 1 Introduction

The solution's $\mathrm{pH}$ can be defined as the negative logarithmic (base 10) of the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ concentration.

$\mathrm{pH}=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\mathrm{pOH}=-\log \left[{\mathrm{OH}}^{-}\right]$

$\mathrm{pH}+\mathrm{pOH}=14$

Step - 2 Explanation

Calculate the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ concentration using the formula: the given $pH$  value is  3.60.

$pH=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$3.6=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]={10}^{(-3.6)}$

$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]=2.5\times {10}^{-4}\mathrm{M}$