Q. 10.64 - An Introduction to General, Organic, and Biological Chemistry

Question

When food enters the stomach,$\mathrm{HCl}$ is released and the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ of the stomach fluid rises to $4\times {10}^{-2}\mathrm{M}$. What is the $\mathrm{pH}$ of the stomach fluid?

Step-by-Step Solution

Answer

 The gastric fluid's pH text is 1.4.

Step - 1 Given information

• The solution's $\mathrm{pH}$ can be defined as the negative logarithmic (base 10) of the $\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$ concentration.

         $\mathrm{pH}=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

         $\mathrm{pOH}=-\log \left[{\mathrm{OH}}^{-}\right]$

         $\mathrm{pH}+\mathrm{pOH}=14$

step - 2 Explanation

• The stomach fluid concentration is $2.0\times {10}^{-4}\mathrm{M}$. Use the following formula to calculate the $\mathrm{pH}$ solution:

         $pH=-\log \left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]$

               $=-\log \left[4.0\times {10}^{-2}\right]$

               $=2-\log (4.0)$

               $=2-0.6$0

               $=1.4$

As a result, the stomach fluid's pH text is 1.4.