Problem 99
Question
The projections of a vector on the three coordinate axis are \(6,-3,2\) respectively. The direction cosines of the vector are (A) \(6,-3,2\) (B) \(\frac{6}{5},-\frac{3}{5}, \frac{2}{5}\) (C) \(\frac{6}{7},-\frac{3}{7}, \frac{2}{7}\) (D) \(-\frac{6}{7},-\frac{3}{7}, \frac{2}{7}\)
Step-by-Step Solution
Verified Answer
Option (C): \(\frac{6}{7}, -\frac{3}{7}, \frac{2}{7}\).
1Step 1: Understand the Problem
We need to find the direction cosines of a vector given its projections on the x, y, and z axes. The projections are 6 on the x-axis, -3 on the y-axis, and 2 on the z-axis.
2Step 2: Recall the Formula for Direction Cosines
The direction cosines of a vector \(\vec{a} = (a_1, a_2, a_3)\) are \(\cos \alpha = \frac{a_1}{\|\vec{a}\|}\), \(\cos \beta = \frac{a_2}{\|\vec{a}\|}\), \(\cos \gamma = \frac{a_3}{\|\vec{a}\|}\), where \(\|\vec{a}\|\) is the magnitude of the vector.
3Step 3: Calculate the Magnitude of the Vector
Use the formula for the magnitude of a vector: \[ \|\vec{a}\| = \sqrt{(a_1)^2 + (a_2)^2 + (a_3)^2} = \sqrt{6^2 + (-3)^2 + 2^2} = \sqrt{36 + 9 + 4} = \sqrt{49} = 7. \]
4Step 4: Compute the Direction Cosines
With the magnitude found, calculate each direction cosine: \[ \cos \alpha = \frac{6}{7}, \] \[ \cos \beta = \frac{-3}{7}, \] \[ \cos \gamma = \frac{2}{7}. \]
5Step 5: Choose the Correct Option
The direction cosines are \(\frac{6}{7}, -\frac{3}{7}, \frac{2}{7}\). Therefore, the correct option is (C).
Key Concepts
Vector MagnitudeProjections on Coordinate Axes3D Coordinate Geometry
Vector Magnitude
The magnitude of a vector is a measure of its size or length. This is crucial in understanding vectors in any dimension, including the 3D space, which is common in physics and engineering applications. To calculate the magnitude of a vector \( \vec{a} = (a_1, a_2, a_3) \), we use the magnitude formula:
\[ \|\vec{a}\| = \sqrt{(a_1)^2 + (a_2)^2 + (a_3)^2} \]
In our exercise, the given projections (components) are 6, -3, and 2. Applying these values, we find:
\[ \|\vec{a}\| = \sqrt{6^2 + (-3)^2 + 2^2} = \sqrt{36 + 9 + 4} = \sqrt{49} = 7 \]
The calculated magnitude helps us in determining other properties of the vector, such as its direction cosines, which tell us the vector’s orientation in space.
\[ \|\vec{a}\| = \sqrt{(a_1)^2 + (a_2)^2 + (a_3)^2} \]
In our exercise, the given projections (components) are 6, -3, and 2. Applying these values, we find:
\[ \|\vec{a}\| = \sqrt{6^2 + (-3)^2 + 2^2} = \sqrt{36 + 9 + 4} = \sqrt{49} = 7 \]
The calculated magnitude helps us in determining other properties of the vector, such as its direction cosines, which tell us the vector’s orientation in space.
Projections on Coordinate Axes
Projections of a vector onto the coordinate axes are essentially its shadows on these axes. If you imagine a vector in a 3D space, its projections are points on the x, y, and z axes. Identifying these projections helps in understanding the vector's influence or contribution in each direction.
- The projection on the x-axis is 6.
- The projection on the y-axis is -3.
- The projection on the z-axis is 2.
3D Coordinate Geometry
3D coordinate geometry extends our understanding of geometric spaces into three dimensions, described using the x, y, and z axes. Working in this space involves handling vector quantities and understanding their properties, like magnitude and direction.
Vectors in 3D are represented as \(\vec{a} = (a_1, a_2, a_3)\), where each component corresponds to how much the vector moves along each axis. This means a vector can be visualized as an arrow in space, originating from the origin \((0, 0, 0)\) and pointing towards \((a_1, a_2, a_3)\).
Key concepts include:
Vectors in 3D are represented as \(\vec{a} = (a_1, a_2, a_3)\), where each component corresponds to how much the vector moves along each axis. This means a vector can be visualized as an arrow in space, originating from the origin \((0, 0, 0)\) and pointing towards \((a_1, a_2, a_3)\).
Key concepts include:
- Direction Cosines: These are the cosines of angles formed by the vector with the respective coordinate axes, given by \(\cos \alpha = \frac{a_1}{\|\vec{a}\|}\), \(\cos \beta = \frac{a_2}{\|\vec{a}\|}\), and \(\cos \gamma = \frac{a_3}{\|\vec{a}\|}\).
- Magnitude: This illustrates the length of a vector, crucial for normalizing the vector for direction calculations.
- Projections: Show how the vector can be aligned or broken down along each axis.
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