Problem 99
Question
For exercises \(85-108\), write \(>\) or \(<\) between the numbers to make a true statement. $$ \frac{5}{8} \quad \frac{2}{3} $$
Step-by-Step Solution
Verified Answer
\frac{5}{8} < \frac{2}{3}
1Step 1 - Find a common denominator
To compare the fractions \(\frac{5}{8}\) and \(\frac{2}{3}\), find a common denominator. The least common multiple (LCM) of 8 and 3 is 24.
2Step 2 - Convert the fractions
Convert each fraction to have the common denominator of 24. For \(\frac{5}{8}\), multiply both the numerator and denominator by 3 to get \(\frac{15}{24}\). For \(\frac{2}{3}\), multiply both the numerator and denominator by 8 to get \(\frac{16}{24}\).
3Step 3 - Compare the numerators
Now compare the numerators of the fractions with the same denominator. Since 15 < 16, \(\frac{15}{24} < \frac{16}{24}\), which means \(\frac{5}{8} < \frac{2}{3}\).
Key Concepts
Understanding Common DenominatorLeast Common Multiple (LCM)Role of the Numerator
Understanding Common Denominator
When comparing or adding fractions, one important step is finding a common denominator. A common denominator is a shared multiple of the denominators of two or more fractions. This makes it easier to directly compare the fractions or perform operations on them.
To find a common denominator for \(\frac{5}{8}\) and \(\frac{2}{3}\), you need a number that both 8 and 3 can divide into without a remainder. We often use the least common multiple (LCM) for this purpose. In this case, the LCM of 8 and 3 is 24. When converting fractions to have a common denominator, you're ensuring both fractions are expressed in a comparable form.
For example:
To find a common denominator for \(\frac{5}{8}\) and \(\frac{2}{3}\), you need a number that both 8 and 3 can divide into without a remainder. We often use the least common multiple (LCM) for this purpose. In this case, the LCM of 8 and 3 is 24. When converting fractions to have a common denominator, you're ensuring both fractions are expressed in a comparable form.
For example:
- Multiply the numerator and denominator of \(\frac{5}{8}\) by 3. This gives \(\frac{15}{24}\).
- Multiply the numerator and denominator of \(\frac{2}{3}\) by 8. This gives \(\frac{16}{24}\).
Least Common Multiple (LCM)
The least common multiple (LCM) is the smallest multiple that is exactly divisible by each one of a set of numbers. It's a shorthand for finding the smallest shared multiple. This is crucial when working with fractions because having the same denominator simplifies many operations.
To find the LCM of two numbers like 8 and 3, list out a few multiples of each:
To find the LCM of two numbers like 8 and 3, list out a few multiples of each:
- Multiples of 8: 8, 16, 24, 32, 40, ...
- Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, ...
Role of the Numerator
The numerator is the top number in a fraction. It indicates how many parts of the whole are being considered. When fractions have the same denominator, you can easily compare them by just looking at the numerators.
In our example, once \(\frac{5}{8}\) and \(\frac{2}{3}\) were converted to \(\frac{15}{24}\) and \(\frac{16}{24}\) respectively, we can compare the numerators 15 and 16 directly. Because 15 is less than 16, we conclude that \(\frac{15}{24} < \frac{16}{24}\). Thus, \(\frac{5}{8} < \frac{2}{3}\).
Comparing numerators becomes straightforward when both fractions share a common denominator. The fraction with the larger numerator represents the larger part of the whole.
In our example, once \(\frac{5}{8}\) and \(\frac{2}{3}\) were converted to \(\frac{15}{24}\) and \(\frac{16}{24}\) respectively, we can compare the numerators 15 and 16 directly. Because 15 is less than 16, we conclude that \(\frac{15}{24} < \frac{16}{24}\). Thus, \(\frac{5}{8} < \frac{2}{3}\).
Comparing numerators becomes straightforward when both fractions share a common denominator. The fraction with the larger numerator represents the larger part of the whole.
Other exercises in this chapter
Problem 96
For exercises 81-96, evaluate. $$ -\frac{7}{11}-\left(-\frac{2}{5}\right) $$
View solution Problem 97
For exercises 15-100, evaluate. $$ -2(6-9)^{2}-5 $$
View solution Problem 99
For exercises 97-114, evaluate. $$ \frac{3}{4}+\frac{1}{6} \div \frac{1}{2}-\frac{1}{3} $$
View solution Problem 100
For exercises \(85-108\), write \(>\) or \(
View solution