Problem 95
Question
The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=1+2 a_{n}, a_{0}=0 $$
Step-by-Step Solution
Verified Answer
The terms are \( a_1 = 1 \), \( a_2 = 3 \), \( a_3 = 7 \), \( a_4 = 15 \), \( a_5 = 31 \).
1Step 1: Understand the Recursive Formula
The sequence is defined by the formula \( a_{n+1} = 1 + 2a_n \) and the initial condition \( a_0 = 0 \). The goal is to compute \( a_n \) for \( n = 1, 2, \, \ldots, \, 5 \).
2Step 2: Compute the First Term
To find \( a_1 \), use the formula with \( n = 0 \): \[ a_{1} = 1 + 2a_0 = 1 + 2(0) = 1. \]
3Step 3: Compute the Second Term
To find \( a_2 \), use the formula with \( n = 1 \): \[ a_2 = 1 + 2a_1 = 1 + 2(1) = 1 + 2 = 3. \]
4Step 4: Compute the Third Term
To find \( a_3 \), use the formula with \( n = 2 \): \[ a_3 = 1 + 2a_2 = 1 + 2(3) = 1 + 6 = 7. \]
5Step 5: Compute the Fourth Term
To find \( a_4 \), use the formula with \( n = 3 \): \[ a_4 = 1 + 2a_3 = 1 + 2(7) = 1 + 14 = 15. \]
6Step 6: Compute the Fifth Term
To find \( a_5 \), use the formula with \( n = 4 \): \[ a_5 = 1 + 2a_4 = 1 + 2(15) = 1 + 30 = 31. \]
Key Concepts
Recurrence RelationInitial ConditionsSequence Computation
Recurrence Relation
A recurrence relation is a mathematical expression that defines a sequence where each term is a function of its preceding terms. In simpler terms, it tells us how to get the next number in a series from the numbers we already know.
In the exercise provided, the sequence is described by the recurrence relation:
This pattern allows us to generate subsequent numbers as long as we know the starting point. Understanding the relation is crucial as it acts as an instruction manual for building the sequence.
In the exercise provided, the sequence is described by the recurrence relation:
- \( a_{n+1} = 1 + 2a_n \)
This pattern allows us to generate subsequent numbers as long as we know the starting point. Understanding the relation is crucial as it acts as an instruction manual for building the sequence.
Initial Conditions
The initial condition in a sequence is the starting point or first value from which all other values are calculated. Initial conditions are essential because they anchor the sequence, providing a known value to plug into the recurrence relation.
In our sequence, the initial condition given is:
Without this, we wouldn't have a fixed point to begin our calculations, rendering the recurrence relation useless for producing subsequent terms.
In our sequence, the initial condition given is:
- \( a_0 = 0 \)
Without this, we wouldn't have a fixed point to begin our calculations, rendering the recurrence relation useless for producing subsequent terms.
Sequence Computation
Sequence computation involves using the recurrence relation and initial conditions to determine the terms of the sequence. Let's walk through computing the first five terms in our sequence step by step:
- For \( n = 1 \), substitute \( a_0 = 0 \) into the relation: \( a_1 = 1 + 2(0) = 1 \).
- For \( n = 2 \), use the value of \( a_1 = 1 \): \( a_2 = 1 + 2(1) = 3 \).
- Next, for \( n = 3 \), take \( a_2 = 3 \): \( a_3 = 1 + 2(3) = 7 \).
- Continue with \( n = 4 \), using \( a_3 = 7 \): \( a_4 = 1 + 2(7) = 15 \).
- Finally, for \( n = 5 \), use \( a_4 = 15 \): \( a_5 = 1 + 2(15) = 31 \).
Other exercises in this chapter
Problem 93
The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=-2 a_{n}, a_{0}=1 $$
View solution Problem 94
The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=-2 a_{n}, a_{0}=2 $$
View solution Problem 96
The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=4-2 a_{n}, a_{0}=\frac{4}{3} $$
View solution Problem 97
The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=\frac{a_{n}}{1+a_{n}}, a_{0}=1 $$
View solution