Problem 95
Question
In Exercises, determine whether the statement is true or false given that \(f(x)=\ln x .\) If it is false, explain why or give an example that shows it is false. $$ f(0)=0 $$
Step-by-Step Solution
Verified Answer
The statement is false because the natural logarithm of zero is undefined.
1Step 1: Interpret the Statement
The statement given is \( f(0)=0 \). This essentially means that if we substitute the value of \( x=0 \) into the function \( f(x)=\ln x \), we are supposed to get the output as 0.
2Step 2: Check the Validity of the Statement
However, a primary understanding of logarithmic functions is that they are not defined for the value 0. Meaning according to the logarithmic function \( \ln x \), there is no value of \( x \) for which \( f(x) \) would be 0.
3Step 3: Conclude the Statement
Therefore, the statement \( f(0)=0 \) is false, because \( f(0)=\ln(0) \) is undefined as logarithmic functions are not defined for 0.
Key Concepts
Natural LogarithmDomain of a FunctionUndefined Expressions
Natural Logarithm
The natural logarithm, denoted as \( \ln x \), is a logarithmic function with a base of \( e \), where \( e \) is an irrational constant approximately equal to 2.71828. The natural logarithm is unique due to its base and has numerous applications in mathematics, especially in calculus and exponential growth models. This function shows how exponentiation and logarithms are inversely related. Specifically, \( \ln x \) can help us find the exponent when \( e \) is raised to a power to get \( x \). For instance, if \( e^y = x \), then \( y = \ln x \). Some important properties of natural logarithms include:
- \( \ln(1) = 0 \) because \( e^0 = 1 \)
- \( \ln(e) = 1 \) because \( e^1 = e \)
- It is only defined for positive real numbers (\( x > 0 \))
Domain of a Function
Understanding the domain of a function is essential for correctly solving mathematical problems. The domain refers to all the permissible input values that a function can accept. For the natural logarithm function, \( \ln x \), the domain only includes positive real numbers: \( x > 0 \). This means \( \ln x \) cannot take zero or negative numbers as inputs. If you try to input \( x = 0 \, \text{or} \, x < 0 \), the result is undefined. This restriction arises because the logarithm measures how many times we multiply the base, \( e \), to get to \( x \). Since zero and negative numbers do not have meaningful values in this context, they fall outside the domain. When dealing with any function, clearly identify its domain as a first step:
- Check for restrictions like division by zero.
- Ensure all inputs yield real, defined values.
Undefined Expressions
Undefined expressions, such as \( \ln 0 \), occur when a function receives an input outside its domain. In our exercise, the expression \( f(0) = \ln(0) \) is undefined because \( \ln x \) cannot take zero as an argument according to its domain rules. Here are some points to consider when a function yields undefined expressions:
- Always check the domain of the function first to avoid using invalid inputs.
- If the calculation results in a division by zero or a logarithm of zero/negative number, it will be undefined.
- Understanding why expressions are undefined can help prevent incorrect assumptions in problem-solving, such as assuming \( f(0) = 0 \) when dealing with \( \ln x \).
Other exercises in this chapter
Problem 93
In Exercises, use a graphing utility to verify that the functions are equivalent for \(x>0\). $$ \begin{aligned} &f(x)=\ln \frac{x^{2}}{4} \\ &g(x)=2 \ln x-\ln
View solution Problem 94
In Exercises, use a graphing utility to verify that the functions are equivalent for \(x>0\). $$ \begin{aligned} &f(x)=\ln \sqrt{x\left(x^{2}+1\right)} \\ &g(x)
View solution Problem 96
In Exercises, determine whether the statement is true or false given that \(f(x)=\ln x .\) If it is false, explain why or give an example that shows it is false
View solution Problem 97
In Exercises, determine whether the statement is true or false given that \(f(x)=\ln x .\) If it is false, explain why or give an example that shows it is false
View solution