Problem 94
Question
It The sum of the first 20 terms of an arithmetic sequence with a common difference of 3 is \(650 .\) Find the first term.
Step-by-Step Solution
Verified Answer
The first term of the arithmetic sequence is \(4\).
1Step 1: Understand the Problem
The problem is to find the first term of the arithmetic sequence. The sum of first 20 terms is given as \(650\), and a common difference, \(d\), is provided as \(3\). The formula for the sum of an arithmetic sequence, \(S_n = n/2 * (a_1 + a_n)\), will be used, where \(n\) is the number of terms, \(a_1\) is the first term, and \(a_n\) is the last term.
2Step 2: Apply the Formula
The arithmetic sequence formula \(S_n = n/2 * (a_1 + a_n)\) can be rewritten as \(a_n = (2S_n/n - a_1)\), which represents the \(n\)th term of the sequence. Based on the given data, the number of terms \(n\) is \(20\), \(S_n\) is \(650\), and \(d\) is \(3\). Plugging these into the formula, we get: \(a_n = a_1 + (n-1)*d\). Substituting the known values, we get: \(a_{20} = a_1 + (20-1)*3 = a_1 + 57\).
3Step 3: Substitute the obtained a_n into the sum formula
Now, substitute the obtained \(a_{20}\) into the sum formula: \(S_{20} = 20/2 * (a_1 + a_{20})\). Hence, \(650 = 10*(a_1 + a_1 + 57)\). This gives a simplified equation: \(650 = 20*a_1 + 570\).
4Step 4: Solve for the unknown
Solving the equation for \(a_1\): \(650 - 570 = 20*a_1\). This simplifies to \(80 = 20*a_1\). Finally, finding the value of \(a_1\) by dividing 80 by 20, we get \(a_1=4\).
5Step 5: Conclusion
Submit the answer as the first term of this arithmetic sequence, which is \(4\).
Key Concepts
First TermSum of TermsCommon DifferenceSequence Formula
First Term
In an arithmetic sequence, the first term, denoted by \(a_1\), is the starting point of the sequence. It's incredibly important in determining all subsequent terms. An arithmetic sequence is a series of numbers in which each term increases by a constant amount known as the common difference.To find the first term when the sum of several terms is known, we use related formulas. In the given exercise, after applying these formulas, we solve the equation to determine the value of \(a_1\), which turns out to be 4. This means the sequence begins at 4, and subsequent terms build from this starting point. Understanding how to manipulate equations to find the first term is crucial in mastering arithmetic sequences.
Sum of Terms
The sum of terms in an arithmetic sequence can be found using the formula:\[ S_n = \frac{n}{2} \times (a_1 + a_n) \]where:
- \(S_n\) is the sum of the first \(n\) terms,
- \(n\) is the number of terms to be added,
- \(a_1\) is the first term,
- and \(a_n\) is the last term.
Common Difference
The common difference, often represented as \(d\), is the consistent amount that each term in an arithmetic sequence increases or decreases by. It's calculated by subtracting any term from the subsequent term.In the problem, the common difference is 3. This means each term is 3 more than the one before. Recognizing the common difference is essential for predicting future terms in the sequence or confirming that a sequence is arithmetic.Here’s how the common difference affects a sequence:
- Starting from the first term, each subsequent term is calculated as \(a_1 + d\), \(a_1 + 2d\), and so on.
- For the 20th term, the formula \(a_{20} = a_1 + 19d\) is used, showing the accumulated impact of the common difference across the sequence.
Sequence Formula
The sequence formula for arithmetic sequences enables us to find any term in the sequence or even the sum of terms up to a certain point. It’s expressed as:\[ a_n = a_1 + (n-1)d \]where:
- \(a_n\) indicates the \(n\)th term,
- \(a_1\) is the first term,
- \(d\) is the common difference,
- \(n\) indicates the specific term number we want to find.
Other exercises in this chapter
Problem 93
Use the Binomial Theorem to expand the complex number. Simplify your result. (Remember that \(i=\sqrt{-1 .})\) $$(2-3 i)^{6}$$
View solution Problem 93
Find the sum. $$\sum_{k=1}^{4} 10$$
View solution Problem 94
Prove the identity. $$_{n} C_{r}=\frac{_{n} P_{r}}{r !}$$
View solution Problem 94
Use the Binomial Theorem to expand the complex number. Simplify your result. (Remember that \(i=\sqrt{-1 .})\) \((3-2 i)^{6}\)
View solution