Problem 93
Question
Find the sum. $$\sum_{k=1}^{4} 10$$
Step-by-Step Solution
Verified Answer
The sum of the series \(\sum_{k=1}^{4} 10\) is \(40\).
1Step 1: Understand the sigma notation
Sigma notation provides a way of compactly and precisely expressing any sum, that is, a sequence of things that are all to be added together. The notation itself looks like this: \(\sum_{k=n_1}^{n_2} a_k \). This is simply equal to \(a_{n_1} + a_{n_1+1} + a_{n_1+2} + \cdots + a_{n_2}\). In this exercise, \(\sum_{k=1}^{4} 10\) is the sum of the series and equals \(10 + 10 + 10 + 10\).
2Step 2: Summation calculation
Once we understand the sigma notation and what terms we are summing, we simply add these terms together: \(10 + 10 + 10 + 10 = 40\).
3Step 3: Final Answer
The sum of the given series \(\sum_{k=1}^{4} 10\) is \(40\).
Other exercises in this chapter
Problem 93
Prove the identity. $$_{n} C_{n-1}=_{n} C_{1}$$
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Use the Binomial Theorem to expand the complex number. Simplify your result. (Remember that \(i=\sqrt{-1 .})\) $$(2-3 i)^{6}$$
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It The sum of the first 20 terms of an arithmetic sequence with a common difference of 3 is \(650 .\) Find the first term.
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Prove the identity. $$_{n} C_{r}=\frac{_{n} P_{r}}{r !}$$
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