Problem 94
Question
For any two complex numbers \(z_{1}\) and \(z_{2}\) with \(\left|z_{1}\right| \neq\left|z_{2}\right|\) $$ \left|\sqrt{2} z_{1}+i \sqrt{3} \bar{z}_{2}\right|^{2}+\left|\sqrt{3} \bar{z}_{1}+i \sqrt{2} z_{2}\right|^{2} \text { is } $$ (A) less than \(5\left(\left|z_{1}\right|^{2}+\left|z_{2}\right|^{2}\right)\) (B) greater than \(10\left|z_{1} z_{2}\right|\) (C) equal to \(2\left|z_{1}\right|^{2}+3\left|z_{2}\right|^{2}\) (D) zero
Step-by-Step Solution
Verified Answer
It equals \( 5(|z_1|^2 + |z_2|^2) \). None of the given options match correctly.
1Step 1: Understanding Complex Numbers
Complex numbers are in the form \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. The conjugate of \( z \), denoted \( \bar{z} \), is \( a - bi \). The modulus is given by \( \left| z \right| = \sqrt{a^2 + b^2} \).
2Step 2: Simplifying the First Term
Consider \( \left| \sqrt{2}z_1 + i \sqrt{3} \bar{z}_2 \right|^2 \). Using properties of complex numbers, we have: \[ \left| \sqrt{2}z_1 + i\sqrt{3}\bar{z}_2 \right|^2 = (\sqrt{2}z_1 + i\sqrt{3}\bar{z}_2)(\sqrt{2}\bar{z}_1 - i\sqrt{3}z_2) \]. When you expand this, using \( z\bar{z} = |z|^2 \), and keeping imaginary and real parts separate, leads to \( 2|z_1|^2 + 3|z_2|^2 \).
3Step 3: Simplifying the Second Term
Now consider \( \left| \sqrt{3} \bar{z}_1 + i \sqrt{2} z_2 \right|^2 \). Similarly, we have \[ (\sqrt{3}\bar{z}_1 + i\sqrt{2}z_2)(\sqrt{3}z_1 - i\sqrt{2}\bar{z}_2) \]. Expanding results in \( 3|z_1|^2 + 2|z_2|^2 \).
4Step 4: Adding Results
Combine the results from Steps 2 and 3: \[ 2|z_1|^2 + 3|z_2|^2 + 3|z_1|^2 + 2|z_2|^2 = 5|z_1|^2 + 5|z_2|^2 \]. Therefore, the sum simplifies as: \( 5 \left( |z_1|^2 + |z_2|^2 \right) \).
5Step 5: Comparing with Given Options
Review the options given: (A) is less than \( 5(|z_1|^2 + |z_2|^2) \), (C) is equal to \( 2|z_1|^2 + 3|z_2|^2 \). From simplification, we found the expression equals \( 5(|z_1|^2 + |z_2|^2) \). Therefore, the correct option is neither.
Key Concepts
Modulus of Complex NumbersConjugate of Complex NumbersProperties of Complex Numbers
Modulus of Complex Numbers
In complex numbers, the modulus is a crucial concept that measures the "size" or "length" of a complex number. For any complex number in the form \( z = a + bi \), where \( a \) and \( b \) are real numbers, the modulus is represented by \( |z| \) and is calculated using the formula:
\[|z| = \sqrt{a^2 + b^2}\]This represents the distance of the complex number from the origin in the complex plane. It can be visualized as the hypotenuse of a right-angled triangle, with \( a \) and \( b \) being the other two sides.
\[|z| = \sqrt{a^2 + b^2}\]This represents the distance of the complex number from the origin in the complex plane. It can be visualized as the hypotenuse of a right-angled triangle, with \( a \) and \( b \) being the other two sides.
- The modulus is always a non-negative real number.
- A complex number has a modulus of zero if and only if it is the origin, i.e., \( z = 0 + 0i \).
Conjugate of Complex Numbers
The conjugate of a complex number helps to simplify algebraic expressions, especially when division of complex numbers is involved or when finding the modulus. For a complex number \( z = a + bi \), its conjugate, denoted \( \bar{z} \), is:
\( \bar{z} = a - bi \)This operation essentially reflects the number across the real axis in the complex plane. Conjugates have several notable properties:
\( \bar{z} = a - bi \)This operation essentially reflects the number across the real axis in the complex plane. Conjugates have several notable properties:
- The modulus of a complex number and its conjugate are identical, i.e., \( |z| = |\bar{z}| \).
- When you multiply a complex number with its conjugate, the result is always real, given by: \[ z\bar{z} = a^2 + b^2 = |z|^2 \]
- Conjugates simplify the process of rationalizing the denominator in complex fractions.
Properties of Complex Numbers
Complex numbers abide by a set of rules that are extensions of real number properties but include considerations for the imaginary unit \( i \). Among these properties:
- **Commutativity and Associativity:** Like real numbers, complex addition and multiplication are commutative and associative. This means you can change the order of operation without affecting the outcome.- **Distributive Property:** Distributing over addition holds as well, \((z_1+z_2)z_3 = z_1z_3 + z_2z_3\).- **Multiplicative Identity and Inverses:** The multiplicative identity is \(1\), and each non-zero complex number \(z\) has a multiplicative inverse \(1/z\) such that \(z \times (1/z) = 1\).In specific terms, when addressing a complex number like \( \sqrt{2}z_1 + i\sqrt{3}\bar{z}_2 \), we utilize these properties to simplify expressions by expanding terms using distributive and conjugate properties. This makes simplification possible, ultimately leading to a clearer comparison of the expressions as done in the problem's step-by-step solution.
- **Commutativity and Associativity:** Like real numbers, complex addition and multiplication are commutative and associative. This means you can change the order of operation without affecting the outcome.- **Distributive Property:** Distributing over addition holds as well, \((z_1+z_2)z_3 = z_1z_3 + z_2z_3\).- **Multiplicative Identity and Inverses:** The multiplicative identity is \(1\), and each non-zero complex number \(z\) has a multiplicative inverse \(1/z\) such that \(z \times (1/z) = 1\).In specific terms, when addressing a complex number like \( \sqrt{2}z_1 + i\sqrt{3}\bar{z}_2 \), we utilize these properties to simplify expressions by expanding terms using distributive and conjugate properties. This makes simplification possible, ultimately leading to a clearer comparison of the expressions as done in the problem's step-by-step solution.
Other exercises in this chapter
Problem 92
If \(a, b, c, p, q, r\) are three non-zero complex numbers such that \(\frac{p}{a}+\frac{q}{b}+\frac{r}{c}=1+i\) and \(\frac{a}{p}+\frac{b}{q}+\frac{c}{r}=0\),
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If \(z_{1}\) and \(z_{2}\) are the two complex roots of equal magnitude and their arguments differ by \(\frac{\pi}{2}\), of the quadratic equation \(a x^{2}+b x
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