Problem 92
Question
When plants are grown at high densities, we often observe that the number of plants decreases as plant weights increase (due to plant growth). If we plot the logarithm of the total aboveground dry-weight biomass per plant, \(\log w\), against the logarithm of the density of survivors, \(\log d\) (base 10 ), a straight line with slope \(-3 / 2\) results. Find the equation that relates \(w\) and \(d\), assuming that \(w=1 \mathrm{~g}\) when \(d=10^{3} \mathrm{~m}^{-2}\) In Problems 93-98, find each functional relationship on the basis of the given graph.
Step-by-Step Solution
Verified Answer
The relationship is \( w = \frac{31622.8}{d^{3/2}} \).
1Step 1: Understand the problem and setup variables
We need to find the functional relationship between plant weight, \(w\), and plant density, \(d\). We are given the linear relationship \( \log w = m \log d + c \) with slope \(m = -\frac{3}{2}\). We're also given that when \(d = 10^3\), \(w = 1\) gram.
2Step 2: Express the linear relationship using log properties
The given slope of \(-\frac{3}{2}\) suggests a line equation of the form \( \log w = -\frac{3}{2} \log d + c \). Here, \(c\) is a constant that we need to determine using the given condition (\(w = 1\) when \(d = 10^3\)).
3Step 3: Substitute the given point (condition)
Since \(w = 1\) gram when \(d = 10^3\), we substitute these into our equation: \( \log 1 = -\frac{3}{2} \log (10^3) + c \). Note that \(\log 1 = 0\) and \(\log (10^3) = 3\).
4Step 4: Solve for constant \(c\)
From the equation \(0 = -\frac{3}{2} \times 3 + c\), we get \( 0 = -\frac{9}{2} + c \). Solving for \(c\), we find \(c = \frac{9}{2}\).
5Step 5: Rewrite the log equation
Replacing \(c\) in the log equation gives us \( \log w = -\frac{3}{2} \log d + \frac{9}{2}\).
6Step 6: Exponentiate to find the relationship
To find the relationship between \(w\) and \(d\), we exponentiate both sides of the equation: \[ w = 10^{-\frac{3}{2} \log d + \frac{9}{2}} = 10^{\frac{9}{2}} \times d^{-\frac{3}{2}} \].
7Step 7: Simplify the relationship
Simplifying further, we find\[ w = \frac{10^{9/2}}{d^{3/2}} = \frac{31622.8}{d^{3/2}} \]. Thus, the relationship between \(w\) and \(d\) is \[ w = \frac{31622.8}{d^{3/2}} \].
Key Concepts
Plant DensityBiomass EstimationLogarithmic Functions in Biology
Plant Density
Plant density is an essential concept in ecology that represents the number of plants within a given area. Understanding plant density helps ecologists analyze how plants compete for resources such as sunlight, water, and soil nutrients.
High plant density means there are many plants in a small area. This often results in fierce competition, leading to some plants not getting enough resources.
High plant density means there are many plants in a small area. This often results in fierce competition, leading to some plants not getting enough resources.
- When plants can't get enough resources, they may not grow as large, leading to reduced biomass.
- Different plants have varying optimal densities, where they grow best without much competition.
Biomass Estimation
Biomass estimation in plant ecology provides insight into the total mass of living plant material in an area, usually measured in terms of dry weight. It helps scientists understand the productivity and health of an ecosystem.
For a practical estimation, several factors are considered:
For a practical estimation, several factors are considered:
- Dry-weight biomass typically involves measuring the weight of plants after removing all the water content, providing a more stable and reproducible metric.
- Biomass is affected by factors like plant size, density, and overall health.
Logarithmic Functions in Biology
Logarithmic functions are essential tools used in biology for modeling growth and other exponential relationships. These functions are especially useful for dealing with large ranges of values, such as densities and growth rates, which can vary significantly.
In our exercise, the logarithmic relationship is used to analyze how biomass per plant and plant density relate. We plot \(\log w\) against \(\log d\) and find a straight line, indicating a power-law relationship. This simplified form allows for ease of understanding and interpretation:
In our exercise, the logarithmic relationship is used to analyze how biomass per plant and plant density relate. We plot \(\log w\) against \(\log d\) and find a straight line, indicating a power-law relationship. This simplified form allows for ease of understanding and interpretation:
- The slope of such a line gives insight into the rate and direction of change between factors. In this case, a slope of \(-\frac{3}{2}\) suggests an inverse relationship between biomass per plant and plant density.
- Logarithms transform multiplicative relationships into additive ones, simplifying the complexity into a linear model.
Other exercises in this chapter
Problem 91
In Problems \(91-96\), for each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\sin x\) and \(y=2 \sin
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Simplify each expression and write it in the standard form \(a+b i\). \((6-i)(6+i)\)
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For each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\sin x\) and \(y=\sin (2 x)\)
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Simplify each expression and write it in the standard form \(a+b i\). \((-4-3 i)(4+2 i)\)
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