Problem 92
Question
Simplify each expression and write it in the standard form \(a+b i\). \((-4-3 i)(4+2 i)\)
Step-by-Step Solution
Verified Answer
The simplified expression is
\(-10 - 20i\).
1Step 1: Distribute Each Term in the First Expression
The given expression is \((-4-3i)(4+2i)\). Start by distributing the first term \(-4\) over the terms of the second expression \((4 + 2i)\): \(-4 \times 4 = -16\) and \(-4 \times 2i = -8i\).
2Step 2: Distribute the Imaginary Term
Now, distribute the \(-3i\) over the terms of the second expression \((4 + 2i)\): \((-3i) \times 4 = -12i\)and\((-3i) \times (2i) = -6i^2\).Remember that \(i^2 = -1\),so \(-6i^2 = 6\).
3Step 3: Combine Like Terms
Combine the real and imaginary parts from the results of the distribution.Real part:\(-16 + 6 = -10\).Imaginary part:\(-8i - 12i = -20i\).
4Step 4: Write in Standard Form
The simplified expression is the sum of the real part and the imaginary part: \(-10 - 20i\).Writing in the standard form \(a + bi\),we have: \(-10 + (-20i)\).
Key Concepts
Simplifying ExpressionsStandard FormImaginary Numbers
Simplifying Expressions
Simplifying expressions in mathematics is akin to tidying up a room—it involves combining like terms and reducing the complexity of expressions to make them easier to understand or evaluate. When working with complex numbers, this process is essential. Complex numbers have both real and imaginary components, typically denoted as \(a+bi\). To simplify, we distribute each term across others, then combine all similar terms.
- Distribution Process: Each term in one of the parentheses is multiplied by every term in the other. This method is commonly referred to as the FOIL method (First, Outer, Inner, Last) when extending to binomials.
- Combining Like Terms: After distribution, terms are combined based on their components—real parts go with real parts, imaginary with imaginary.
- Simplification of \(i^2\): A key mistake is forgetting that \(i^2 = -1\). Remembering this is crucial when simplifying terms like \(-6i^2\), which becomes \(6\) since \(-6 imes (-1) = 6\).
Standard Form
The standard form of a complex number is a neat way to write complex numbers, and it is represented as \(a + bi\). This standardization is crucial because it allows mathematicians to easily understand and manipulate complex numbers and avoids any confusion. Let's break this down:
- Real Component \(a\): This is the first term and is a real number. It's what makes the complex number grounded in the real number system.
- Imaginary Component \(bi\): The second term, where \(b\) is a real number, and \(i\) is the imaginary unit \(\sqrt{-1}\). This part defines the number's position in the imaginary realm.
Imaginary Numbers
Imaginary numbers might sound like something out of a sci-fi novel, but in mathematics, they are very real tools used to solve equations that can't be solved using real numbers alone. Imaginary numbers are based on the imaginary unit \(i\), which is defined as \(\sqrt{-1}\).
- Imaginary Unit \(i\): This is a fundamental concept, where \(i^2 = -1\). It denotes an extension of the real number system, allowing for solutions beyond real numbers.
- Why Use Imaginary Numbers? They enable the taking of square roots of negative numbers, essential in various fields like engineering and physics, where real numbers fall short.
- Applications: Beyond pure mathematics, imaginary numbers have practical applications. They are crucial for solving electrical problems, signal processing, and even quantum physics.
Other exercises in this chapter
Problem 92
When plants are grown at high densities, we often observe that the number of plants decreases as plant weights increase (due to plant growth). If we plot the lo
View solution Problem 92
For each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\sin x\) and \(y=\sin (2 x)\)
View solution Problem 93
For each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\cos x\) and \(y=2 \cos x\)
View solution Problem 93
Let z \(=3-2 i\), \(u=-4+3 i, v=3+5 i\), and \(w=1-i .\) Compute the following expressions: \(\bar{z}\)
View solution