Problem 91
Question
Perform the indicated operations. $$ \frac{\left(a^{2} b^{3}\right)^{4}}{\left(a b^{4}\right)^{3}} \cdot \frac{(a b)^{3}}{\left(a^{4} b\right)^{2}} $$
Step-by-Step Solution
Verified Answer
The answer is \( b \).
1Step 1 - Simplify the First Fraction
Start by simplifying \ \ \(\frac{\left(a^{2} b^{3}\right)^{4}}{\left(a b^{4}\right)^{3}}\).Use the power rule \( (x^m)^n = x^{m \cdot n} \).\[ \frac{\left(a^{2} b^{3}\right)^{4}}{\left(a b^{4}\right)^{3}} = \frac{a^{2 \cdot 4} b^{3 \cdot 4}}{a^{1 \cdot 3} b^{4 \cdot 3}} = \frac{a^8 b^{12}}{a^3 b^{12}}. \]
2Step 2 - Cancel Common Terms in the First Fraction
In the fraction, cancel common terms \( b^{12} \) from the numerator and the denominator. Simplify \ \ \( \frac{a^8 b^{12}}{a^3 b^{12}} = \frac{a^8}{a^3} = a^{8-3} = a^5. \)
3Step 3 - Simplify the Second Fraction
Now simplify \ \( \frac{(a b)^{3}}{\left(a^{4} b\right)^{2}}. \) Again, use the power rule.\[ \frac{(a b)^{3}}{\left(a^{4} b\right)^{2}} = \frac{a^3 b^3}{a^{4 \cdot 2} b^2} = \frac{a^3 b^3}{a^8 b^2}. \]
4Step 4 - Cancel Common Terms in the Second Fraction
In the fraction, cancel common terms \( b^2 \) from the numerator and the denominator. Simplify: \ \( \frac{a^3 b^3}{a^8 b^2} = \frac{a^3}{a^8} \cdot \frac{b^3}{b^2} = a^{3-8} b^{3-2} = a^{-5} b. \)
5Step 5 - Multiply the Simplified Fractions
Combine the simplified results from Steps 2 and 4: \( a^5 \cdot a^{-5} b = a^{5-5} b = a^0 b = b. \)
Key Concepts
Exponent RulesSimplificationFraction OperationsPower Rule
Exponent Rules
Exponent rules are essential when working with algebraic expressions involving powers. They help us simplify and manipulate expressions efficiently. The most commonly used exponent rules include:
- Product of Powers: \( x^m \times x^n = x^{m+n} \)
- Quotient of Powers: \( \frac{x^m}{x^n} = x^{m-n} \)
- Power of a Power: \( (x^m)^n = x^{m \cdot n} \)
- Power of a Product: \( (xy)^m = x^m y^m \)
Simplification
Simplification in algebra often involves reducing expressions to their simplest form. It includes combining like terms, cancelling common factors, and using exponent rules. The primary goal is to make equations and expressions more manageable. In the given example, we use simplification throughout the process:
1. First, we applied the power rule to simplify both the numerator and the denominator.
2. Then, we cancelled out common terms like \( b^{12} \) in the first fraction.
3. Each fraction was reduced further until we reached a simplified form such as \( \frac{a^8}{a^3} = a^5 \). By breaking down each step, we can focus on reducing parts of the expression one at a time, ensuring accuracy and clarity.
1. First, we applied the power rule to simplify both the numerator and the denominator.
2. Then, we cancelled out common terms like \( b^{12} \) in the first fraction.
3. Each fraction was reduced further until we reached a simplified form such as \( \frac{a^8}{a^3} = a^5 \). By breaking down each step, we can focus on reducing parts of the expression one at a time, ensuring accuracy and clarity.
Fraction Operations
When dealing with fractions in algebra, it becomes necessary to manipulate both the numerators and denominators appropriately. Fraction operations often involve:
- Finding a common denominator when adding or subtracting fractions.
- Multiplying the numerators and denominators separately when multiplying fractions.
- Dividing by multiplying with the reciprocal of the divisor fraction.
Power Rule
The power rule is vital when working with expressions wrapped in parentheses that are raised to an exponent. The power rule states that when a term with an exponent is raised to another power, you multiply the exponents: \( (x^m)^n = x^{m \cdot n} \). The rule simplifies evaluating algebraic expressions significantly.
For instance, given \( \frac{ \left( a^2 b^3 \right)^4 }{ \left( a b^4 \right)^3 } \), we apply the power rule to get \( \frac{ a^{2 \cdot 4} b^{3 \cdot 4} }{ a^{1 \cdot 3} b^{4 \cdot 3} } = \frac{ a^8 b^{12} }{ a^3 b^{12} } \). This simplifies each term correctly. In subsequent steps, the rule was also used to simplify \( \frac{ (a b)^3 }{ \left( a^4 b \right)^2 } = \frac{ a^3 b^3 }{ a^{8} b^2 }\). Applying the power rule correctly leads to easier simplification and manipulation of algebraic expressions.
For instance, given \( \frac{ \left( a^2 b^3 \right)^4 }{ \left( a b^4 \right)^3 } \), we apply the power rule to get \( \frac{ a^{2 \cdot 4} b^{3 \cdot 4} }{ a^{1 \cdot 3} b^{4 \cdot 3} } = \frac{ a^8 b^{12} }{ a^3 b^{12} } \). This simplifies each term correctly. In subsequent steps, the rule was also used to simplify \( \frac{ (a b)^3 }{ \left( a^4 b \right)^2 } = \frac{ a^3 b^3 }{ a^{8} b^2 }\). Applying the power rule correctly leads to easier simplification and manipulation of algebraic expressions.
Other exercises in this chapter
Problem 90
In place of each question mark in Exercises \(75-92,\) put an expression that will make the rational expressions equivalent. $$\frac{x-3}{x^{2}-9}=\frac{1}{?}$$
View solution Problem 91
Solve each problem. Pleasing painting. The ancient Greeks often used the ratio of length to width for a rectangle as 7 to 6 to give the rectangle a pleasing sha
View solution Problem 91
Perform the indicated operations. $$ \frac{2 x+1}{6 x^{2}-5 x+1}+\frac{2 x-1}{6 x^{2}+x-1} $$
View solution Problem 91
In place of each question mark in Exercises \(75-92,\) put an expression that will make the rational expressions equivalent. $$\frac{1}{x-1}=\frac{?}{x^{3}-1}$$
View solution