Problem 9
Question
Find an equation that shifts the graph of \(f\) by the desired amounts. Do not simplify. Graph \(f\) and the shifted graph in the same \(xy\)-plane. \(f(x)=x^{2} ;\) right 2 units, downward 3 units
Step-by-Step Solution
Verified Answer
The shifted equation is \(g(x) = (x - 2)^2 - 3\).
1Step 1: Original Function
The given function is \(f(x) = x^2\). This represents a parabola with its vertex at the origin (0, 0) and opens upwards.
2Step 2: Shift Right by 2 Units
To shift a function horizontally, you replace \(x\) with \(x - h\). For a shift to the right by 2 units, replace \(x\) with \(x - 2\). Thus, the function becomes \(f(x) = (x - 2)^2\).
3Step 3: Shift Downward by 3 Units
To shift a function vertically downward, you subtract \(k\) from the function. For a shift downward by 3 units, subtract 3 from the current function. The equation becomes \[g(x) = (x - 2)^2 - 3\].
4Step 4: Graphing the Functions
Graph the original function \(f(x) = x^2\) and the shifted function \(g(x) = (x - 2)^2 - 3\) on the same \(xy\)-plane. The graph of \(f(x) = x^2\) is a parabola opening upwards with vertex at (0, 0). The graph of \(g(x) = (x - 2)^2 - 3\) is the same parabola shifted right by 2 units and downward by 3 units, with vertex at (2, -3).
Key Concepts
Understanding Horizontal ShiftsExploring Vertical ShiftsGraphing Parabolas
Understanding Horizontal Shifts
When we talk about horizontal shifts in functions, we're essentially moving the function left or right along the x-axis. Imagine you have a parabola like the function \(f(x) = x^2\), which centers its vertex at the origin, point (0, 0). To achieve a horizontal shift, you adjust the input \(x\) of the function by adding or subtracting from it.
- If you want the function to move to the right, you replace \(x\) with \(x - h\), where \(h\) is the number of units you intend to shift. So, for \(h = 2\), our new function would be \(f(x) = (x - 2)^2\).
- Conversely, shifting the function to the left involves replacing \(x\) with \(x + h\). For example, \(f(x) = (x + 2)^2\) would shift the parabola to the left by 2 units.
Exploring Vertical Shifts
Vertical shifts in a function involve moving the function up or down along the y-axis. This adjustment directly adds or subtracts a value to the whole function output. For example, with the function \(f(x) = x^2\), we look at vertical shifts like so:
- To shift the function upwards, you add a positive constant \(k\). So, \(f(x) = x^2 + k\), where \(k\) represents how far we want to move up.
- To shift it downwards, subtract that constant: \(f(x) = x^2 - k\). In our case, for a downward shift of 3 units, the function becomes \((x - 2)^2 - 3\).
Graphing Parabolas
Graphing parabolas like \(f(x) = x^2\) is all about visualizing these shifts. Begin with the original parabolic function where the vertex sits at (0, 0) and it opens upwards from there. As you incorporate shifts:
- The horizontal shift acts first, repositioning the vertex sideways. For \(f(x) = (x-2)^2\), the vertex moves right to (2,0).
- Then, with the vertical shift, the whole parabola shifts up or down. Combining both shifts, our example becomes \(g(x) = (x-2)^2 - 3\), placing the vertex at (2, -3).
Other exercises in this chapter
Problem 8
Exercises \(1-28:\) Solve the quadratic equation. Check your answers for Exercises \(1-12\). $$ 4 z^{2}=7-27 z $$
View solution Problem 9
Simplify by using the imaginary unit \(i\). $$ \sqrt{-54} $$
View solution Problem 9
Exercises \(1-28:\) Solve the quadratic equation. Check your answers for Exercises \(1-12\). $$ x(3 x+14)=5 $$
View solution Problem 10
Simplify by using the imaginary unit \(i\). $$ \sqrt{-28} $$
View solution