Problem 9
Question
Exer. 3-10: Find the \(n\)th term, the fifth term, and the tenth term of the arithmetic sequence. $$ \ln 3, \ln 9, \ln 27, \ln 81, \ldots $$
Step-by-Step Solution
Verified Answer
\( a_n = n \cdot \ln 3 \); Fifth term: \( 5 \cdot \ln 3 \); Tenth term: \( 10 \cdot \ln 3 \).
1Step 1: Determine the Common Difference
The given sequence is \, \( \ln 3 \), \( \ln 9 \), \( \ln 27 \), \( \ln 81 \), \ldots Identify the common difference between consecutive terms. Calculate: \( \ln 9 - \ln 3 = \ln \left( \frac{9}{3} \right) = \ln 3 \). The common difference \( d \) is \( \ln 3 \).
2Step 2: Write the Formula for the \(n\)th Term
An arithmetic sequence's \(n\)th term is given by \( a_n = a_1 + (n-1) \cdot d \).The first term \( a_1 = \ln 3 \) and the common difference \( d = \ln 3 \).Thus, the formula becomes \( a_n = \ln 3 + (n-1) \cdot \ln 3 = n \cdot \ln 3 \).
3Step 3: Find the Fifth Term
Substitute \( n = 5 \) into the \(n\)th term formula: \( a_5 = 5 \cdot \ln 3 \).
4Step 4: Find the Tenth Term
Substitute \( n = 10 \) into the \(n\)th term formula: \( a_{10} = 10 \cdot \ln 3 \).
Key Concepts
Common DifferenceNth Term FormulaLogarithmsSequence Terms Calculation
Common Difference
An arithmetic sequence is a series of numbers in which the difference between any two successive members is constant. This consistent difference is known as the common difference. In our exercise involving natural logarithms of powers of 3, the sequence given is \( \ln 3, \ln 9, \ln 27, \ln 81, \ldots \). To find the common difference \( d \), we subtract the logarithm of the first term from the logarithm of the second term:
- \( \ln 9 - \ln 3 = \ln \left( \frac{9}{3} \right) = \ln 3 \)
Nth Term Formula
The formula for finding the \(n\)th term of an arithmetic sequence is important because it allows calculation of any term in the sequence without listing every single term. For an arithmetic sequence, this formula is given by:
- \( a_n = a_1 + (n-1) \cdot d \)
- \( a_n = \ln 3 + (n-1) \cdot \ln 3 = n \cdot \ln 3 \)
Logarithms
Logarithms are mathematical operations that are the reverse of exponentiation. The notation \( \ln \) specifically refers to the natural logarithm, which has a base of \( e \) (approximately 2.718). When dealing with sequences that involve logarithms, like the one in this exercise, understanding properties of logarithms can be very helpful. For instance, the property \( \ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) \) is instrumental in simplifying and identifying the common difference in logarithmic sequences. Logarithms can help turn multiplicative processes into additive ones, which simplifies many calculations and makes solving problems related to sequences of geometric growth more manageable.
Sequence Terms Calculation
Calculating specific terms in an arithmetic sequence once you have the \(n\)th term formula is straightforward. Here's how you can find specific terms using the formula \( a_n = n \cdot \ln 3 \):
- To find the fifth term, we set \( n = 5 \). Then \( a_5 = 5 \cdot \ln 3 \), which gives us the value of the fifth term.
- To find the tenth term, set \( n = 10 \). Thus, \( a_{10} = 10 \cdot \ln 3 \), yielding the tenth term.
Other exercises in this chapter
Problem 9
Exer. 9-10: Find the number of possible color arrangements for the 12 given disks, arranged in a row. 5 black, 3 red, 2 white, 2 green
View solution Problem 9
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ 1^{2}+2^{2}+3^{2}+\cdots+n^{2}=\frac{n(n+1)(2 n+1)}{6} $$
View solution Problem 10
Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$162,-54,18,-6, \ldots$$
View solution Problem 10
Exer. 9-10: Find the number of possible color arrangements for the 12 given disks, arranged in a row. 3 black, 3 red, 3 white, 3 green
View solution