Problem 10
Question
Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$162,-54,18,-6, \ldots$$
Step-by-Step Solution
Verified Answer
5th term is 2, 8th term is \(-\frac{2}{27}\).
1Step 1: Identify the first term
The first term of the sequence is the initial term given, which is 162. This is denoted as \(a_1 = 162\).
2Step 2: Find the common ratio
To find the common ratio \(r\), divide the second term by the first term: \(-54 \div 162 = -\frac{1}{3}\). Thus, \(r = -\frac{1}{3}\).
3Step 3: General formula for the nth term
The formula for the nth term of a geometric sequence is given by \(a_n = a_1 \, r^{n-1}\). Here, \(a_1 = 162\) and \(r = -\frac{1}{3}\).
4Step 4: Calculate the nth term formula
Substitute \(a_1\) and \(r\) into the formula: \(a_n = 162 \, \left(-\frac{1}{3}\right)^{n-1}\). This will give us the nth term for any \(n\).
5Step 5: Calculate the fifth term
Substitute \(n = 5\) into the nth term formula: \[a_5 = 162 \, \left(-\frac{1}{3}\right)^{5-1} = 162 \, \left(-\frac{1}{3}\right)^4 = 162 \, \times \frac{1}{81} = 2\].
6Step 6: Calculate the eighth term
Substitute \(n = 8\) into the nth term formula: \[a_8 = 162 \, \left(-\frac{1}{3}\right)^{8-1} = 162 \, \left(-\frac{1}{3}\right)^7\].Calculate \((-\frac{1}{3})^7 = -\frac{1}{2187}\), hence \[a_8 = 162 \, \times -\frac{1}{2187} = -\frac{162}{2187} = -\frac{2}{27}\].
Key Concepts
Common Rationth Term FormulaGeometric Progression
Common Ratio
In a geometric sequence, the common ratio is a crucial component. It's the factor by which we multiply one term to obtain the next term in the sequence. To find this ratio, you can simply divide the second term by the first term of the sequence.
For example, if our sequence begins with 162 and the second term is -54, we'd find the common ratio like this:
For example, if our sequence begins with 162 and the second term is -54, we'd find the common ratio like this:
- Divide -54 by 162, which gives you \(-\frac{1}{3}\).
nth Term Formula
The ability to find any term in a geometric sequence relies on a straightforward formula. This formula is structured to make predictions easy once you know the sequence's first term and its common ratio. To find the \( n \)th term, use this formula:
Suppose we have a sequence where the first term \( a_1 \) is 162 and the common ratio \( r \) is -\(\frac{1}{3}\). If we use the formula to find the 5th term, we substitute \( n = 5 \) into the formula:
- \( a_n = a_1 \cdot r^{n-1} \)
Suppose we have a sequence where the first term \( a_1 \) is 162 and the common ratio \( r \) is -\(\frac{1}{3}\). If we use the formula to find the 5th term, we substitute \( n = 5 \) into the formula:
- \( a_5 = 162 \cdot (-\frac{1}{3})^{5-1} = 2 \)
Geometric Progression
A geometric progression is essentially a list of numbers in which each term after the first is found by multiplying the previous one by the common ratio. This type of sequence can appear everywhere—from investments with constant interest rates to biological systems with exponential growth. Understanding the geometric progression:
The beauty of geometric progressions is their predictability and simplicity once you understand the basic pattern. Detecting such structures in datasets or patterns helps in forecasting and making informed decisions in various fields.
- The sequence starts with a starting value or first term \( a_1 \).
- Each subsequent term \( a_n \) is the product of the preceding term and the common ratio \( r \).
The beauty of geometric progressions is their predictability and simplicity once you understand the basic pattern. Detecting such structures in datasets or patterns helps in forecasting and making informed decisions in various fields.
Other exercises in this chapter
Problem 9
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ 1^{2}+2^{2}+3^{2}+\cdots+n^{2}=\frac{n(n+1)(2 n+1)}{6} $$
View solution Problem 9
Exer. 3-10: Find the \(n\)th term, the fifth term, and the tenth term of the arithmetic sequence. $$ \ln 3, \ln 9, \ln 27, \ln 81, \ldots $$
View solution Problem 10
Exer. 9-10: Find the number of possible color arrangements for the 12 given disks, arranged in a row. 3 black, 3 red, 3 white, 3 green
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Evaluate the expression. $$ \left(\begin{array}{l} 8 \\ 4 \end{array}\right) $$
View solution