Problem 9
Question
Complete the solution. Solve \(t=a d+b c\) for \(c\) $$ \begin{aligned} &t-\quad=a d+b c-\\\ &t-a d=\\\ &t-a d\\\ &\frac{t-a d}{b}=\\\ &c= \end{aligned} $$
Step-by-Step Solution
Verified Answer
\( c = \frac{t - a d}{b} \)
1Step 1: Write the Equation
We start with the equation given: \( t = a d + b c \). Our goal is to solve for \( c \).
2Step 2: Isolate the term with c
Subtract \( a d \) from both sides of the equation to isolate the term \( b c \) on the right side: \( t - a d = b c \).
3Step 3: Solve for c
To isolate \( c \), divide both sides of the equation by \( b \). The equation becomes: \( c = \frac{t - a d}{b} \).
Key Concepts
Isolating VariablesEquation ManipulationAlgebraic Expressions
Isolating Variables
In solving linear equations, isolating variables is often a crucial step. It involves rearranging the equation to get the variable of interest alone on one side of the equation. This makes it easier to solve for that variable. For example, consider the equation \( t = a d + b c \). We need to solve for \( c \). The first step is to isolate the term \( b c \) on one side of the equation. By subtracting \( a d \) from both sides, we effectively move \( a d \) to the opposite side:
- Original equation: \( t = a d + b c \)
- Subtract \( a d \) from both sides: \( t - a d = b c \)
Equation Manipulation
Equation manipulation is all about using algebraic operations to transform and simplify equations. It involves applying mathematical operations like addition, subtraction, multiplication, and division to both sides of an equation to shape it into a form that can be more easily solved. In our example, after isolating \( b c \), we manipulate the equation further to solve for \( c \).To solve for \( c \), we need to divide both sides by the coefficient \( b \), which accompanies the variable \( c \). This operation will effectively "cancel out" \( b \) on the side of the equation with \( c \):
- Equation before manipulation: \( t - a d = b c \)
- Divide each side by \( b \): \( \frac{t - a d}{b} = c \)
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations. Understanding how to work with these is key to solving equations. In the equation \( t = a d + b c \), each term—\( a d \), \( b c \), and \( t \)—is an algebraic expression. These expressions can contain coefficients (like \( a \) and \( b \)), which are numbers that modify variables.To work with algebraic expressions, one must be comfortable with rearranging them by:
- Identifying like terms. For example, in \( a d + b c \), neither term can be combined directly because they have different variables.
- Using operations such as addition, subtraction, multiplication, and division. These help in moving parts of the expression around to solve for the variable we are interested in.
Other exercises in this chapter
Problem 8
Fill in the blanks. The ______ _____ of any real number is the distance between the number and zero on a number line.
View solution Problem 8
What arithmetic operations does the expression \(\frac{40-8 n}{5}\) contain? What variable does it contain?
View solution Problem 9
Fill in the blanks. a. An exponent indicates repeated _____. b. Subtraction is the same as adding the _____ of the number being subtracted.
View solution Problem 9
Solve each equation mentally. a. \(x+3=6\) b. \(x-3=6\) c. \(3 x=6\) d. \(\frac{x}{3}=6\)
View solution