Problem 88
Question
Which expression is NOT equivalent to \(\sqrt[4]{4 n^{2}} ?\) \(\begin{array}{llll}{\text { A. }\left(4 n^{2}\right)^{\frac{1}{4}}} & {\text { B. } 2 n^{\frac{1}{2}}} & {\text { C. }(2 n)^{\frac{1}{2}}} & {\text { D. } \sqrt{2 n}}\end{array}\)
Step-by-Step Solution
Verified Answer
Options C and D are NOT equivalent to \(\sqrt[4]{4 n^{2}}\). Therefore, the expressions presented in options C and D are not equivalent to the initial given expression.
1Step 1: Rewrite the main expression
First, rewrite the main expression, \(\sqrt[4]{4 n^{2}}\), as a power to better compare with the given options. This can be written as \((4 n^{2})^{\frac{1}{4}}\).
2Step 2: Break down the main expression
According to the laws of exponents, \((a b)^n = a^n b^n\). Applying this rule to our expression gives us \((4^{\frac{1}{4}}) * (n^{2})^{\frac{1}{4}}\). This simplifies to \(2 * n^{\frac{1}{2}}\) because the fourth root of 4 is 2 and \(n^{2 * \frac{1}{4}} = n^{\frac{1}{2}}\). Also, rearrange the expression to \(2n ^{\frac{1}{2}}\). This is equivalent to option B.
3Step 3: Compare with other options
The other options C and D do not match the simplified expression obtained. Option C equals \(2*\sqrt{n} = 2*n^{\frac{1}{2}}\) which is not equivalent to our main expression \(2n^{\frac{1}{2}}\). For option D, we have \(\sqrt{2n}\), which is equivalent to \(2n^{\frac{1}{2}}\) which is also not equivalent to our main expression. Therefore, options C and D do not match our simplified expression and are not equivalent to the initial given expression \(\sqrt[4]{4 n^{2}}\).
Key Concepts
Understanding ExponentsExploring Equivalent ExpressionsLaws of Exponents
Understanding Exponents
Exponents are a mathematical operation that involves raising numbers to a power. When we say a number like \( n^2 \), it means \( n \) is multiplied by itself once, making \( n \times n \). The number above the base, called the exponent, tells us how many times to multiply the base. This can greatly simplify repeated multiplication.
For example, \( 3^4 \) means \( 3 \times 3 \times 3 \times 3 \), resulting in 81. Exponents are crucial in algebra for expressing large numbers concisely.
For example, \( 3^4 \) means \( 3 \times 3 \times 3 \times 3 \), resulting in 81. Exponents are crucial in algebra for expressing large numbers concisely.
- **Base**: The number being multiplied.
- **Exponent**: Shows how many times the base is used in multiplication.
- **Power**: The entire expression (e.g., \( 3^4 \)).
Exploring Equivalent Expressions
An equivalent expression in algebra means that two expressions, though looking different, hold the same value when calculated. Finding equivalent expressions is fundamental for solving algebraic equations and simplifying problems.
To determine if two expressions are equivalent, simplify each one and compare. If both expressions reduce to the same simple form, they are equivalent. Consider our exercise, where we are tasked to find which expression is not equivalent to \(\sqrt[4]{4 n^2}\). This can be rewritten in different ways using exponents, yet may or may not be equivalent depending on manipulation.
To determine if two expressions are equivalent, simplify each one and compare. If both expressions reduce to the same simple form, they are equivalent. Consider our exercise, where we are tasked to find which expression is not equivalent to \(\sqrt[4]{4 n^2}\). This can be rewritten in different ways using exponents, yet may or may not be equivalent depending on manipulation.
- **Simplification**: Reducing expressions to simpler terms.
- **Comparison**: Breaking down and comparing simplified forms.
Laws of Exponents
The laws of exponents are rules that govern how we perform operations involving exponents. These laws make computation manageable and allow us to transform expressions.
Here are some fundamental laws of exponents:
Here are some fundamental laws of exponents:
- **Product of Powers Rule**: \( a^m \times a^n = a^{m+n} \)
- **Power of a Power Rule**: \( (a^m)^n = a^{m \times n} \)
- **Power of a Product Rule**: \( (ab)^n = a^n \times b^n \)
- **Quotient of Powers Rule**: \( \frac{a^m}{a^n} = a^{m-n} \)
Other exercises in this chapter
Problem 88
If \((f \circ g)(x)=x^{2}-6 x+8\) and \(g(x)=x-3,\) which expression could represent \(f(x) ?\) $$\begin{array}{llll}{\text { F. } x-4} & {\text { G. } x-1} & {
View solution Problem 88
Solve each equation by factoring. \(3 x^{2}+8 x+4=0\)
View solution Problem 89
Solve using the Quadratic Formula. \(x^{2}-9 x+15=0\)
View solution Problem 89
List all possible rational roots for each equation. Then use the Rational Root Theorem to find each root. $$ 3 x^{3}-5 x^{2}-4 x+4=0 $$
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